Functor provides pattern-based function and method dispatch for Ruby, originally inspired by Topher Cyll's multi gem. 

= Method Functors

To use it in a class:

  class Repeater
    attr_accessor :times
    include Functor::Method
    functor( :repeat, Integer ) { |x| x * @times }
    functor( :repeat, String ) { |s| [].fill( s, 0..@times ).join(' ') }
  end

  r = Repeater.new
  r.times = 5
  r.repeat( 5 )   # => 25
  r.repeat( "-" ) # => "- - - - -"
  r.repeat( 7.3 ) # => ArgumentError!

Warning: This defines a class instance variable <tt>@__functors</tt> behind the scenes as a side-effect. Also, although 
inheritance works within a functor method, super does not. To call the parent method, you need to call it explicitly 
using the <tt>#functors</tt> class method, like this:

  A.functors[ :foo ].apply( self, 'bar' )

= Stand-Alone Functors

You can also define Functor objects directly:

  fib = Functor.new do
    given( 0 ) { 0 }
    given( 1 ) { 1 }
    given( Integer ) { |n| self.call( n - 1 ) + self.call( n - 2 ) }
  end
  
You can use functors directly with functions taking a block like this:

  [ *0..10 ].map( &fib )  # => [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]
  
You can call a functor as a method using #apply:

  fun.apply( obj, 7 )
  
which is actually how the method functors are implemented.

= Pattern Matching

Arguments are matched first using === and then ==, so anything that supports these methods can be matched against. In 
addition, you may pass "guards," any object that responds to #call and which take and object (the argument) and return 
true or false. This allows you to do things like this:

  stripe ||= Functor.new do
    given( lambda { |x| x % 2 == 0 } ) { 'white' }
    given( lambda { |x| x % 2 == 1 } ) { 'silver' }
  end

which will return "white" and "silver" alternately for a sequence of numbers.

= Precedence

Precedence is defined in order of declaration: first-come, first-serve, aka FIFO. Thus, you need to be careful in how 
you define your functor. The Fibonacci example above would not work properly if the Integer pattern was given first. 
That said, it is possible to redefine earlier cases, which, in effect, "demotes" it, as if it had not been declared 
before. So the following will work properly:

  fib = Functor.new do
    given( Integer ) { |n| raise "this would start an infinite loop ..." }
    given( 0 ) { 0 }
    given( 1 ) { 1 }
    # but this will "demote" the Integer pattern and now it will work ...
    given( Integer ) { |n| self.call( n - 1 ) + self.call( n - 2 ) }
  end

This isn't perfect, but it is very easy to predict, simple to implement, and reasonably fast, which other approaches 
(such as implementing a precedence scheme) are not.

= Credits And Support

Functor was written by Dan Yoder, Matthew King, and Lawrence Pit. Send email to dan at zeraweb.com for support or 
questions.