1365-how-many-numbers-are-smaller-than-the-current-number.js

/**
 * 1365. How Many Numbers Are Smaller Than the Current Number
 * https://leetcode.com/problems/how-many-numbers-are-smaller-than-the-current-number/
 * Difficulty: Easy
 *
 * Given the array nums, for each nums[i] find out how many numbers in the array are smaller
 * than it. That is, for each nums[i] you have to count the number of valid j's such that
 * j != i and nums[j] < nums[i].
 *
 * Return the answer in an array.
 */

/**
 * @param {number[]} nums
 * @return {number[]}
 */
var smallerNumbersThanCurrent = function(nums) {
  const sorted = nums.slice().sort((a, b) => a - b);
  return nums.map(num => sorted.indexOf(num));
};