203. Remove Linked List Elements.py

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def removeElements(self, head: Optional[ListNode], val: int) -> Optional[ListNode]:
        dummy_head = ListNode(-1)
        dummy_head.next = head
        curr = dummy_head
        
        while curr.next is not None:
            if curr.next.val == val:
                curr.next = curr.next.next
            else:
                curr = curr.next
        
        return dummy_head.next