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Knapsack.java
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/*
* Dynamic programming algorithm that computes the maximum value that you can obtain from putting n elements (each with integral value and weight) in a knapsack that can fit
* a total of n weight.
*
* Time complexity: O(NM) where N is the number of items and the M is the size of the knapsack
*/
package codebook.dp;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.StringTokenizer;
public class Knapsack {
static BufferedReader br;
static PrintWriter out;
static StringTokenizer st;
public static void main (String[] args) throws IOException {
br = new BufferedReader(new InputStreamReader(System.in));
out = new PrintWriter(new OutputStreamWriter(System.out));
//br = new BufferedReader(new FileReader("in.txt"));
//out = new PrintWriter(new FileWriter("out.txt"));
// number of items
int n = readInt();
// size of knapsack
int m = readInt();
int[] weight = new int[n + 1];
int[] value = new int[n + 1];
int[] dp = new int[m + 1];
for (int i = 1; i <= n; i++) {
weight[i] = readInt();
value[i] = readInt();
}
for (int i = 1; i <= n; i++)
// 0-1 knapsack; for unbounded then iterate the opposite way
for (int j = m; j >= 0; j--)
if (j - weight[i] >= 0)
dp[j] = Math.max(dp[j], dp[j - weight[i]] + value[i]);
out.println(dp[m]);
out.close();
}
static String next () throws IOException {
while (st == null || !st.hasMoreTokens())
st = new StringTokenizer(br.readLine().trim());
return st.nextToken();
}
static long readLong () throws IOException {
return Long.parseLong(next());
}
static int readInt () throws IOException {
return Integer.parseInt(next());
}
static double readDouble () throws IOException {
return Double.parseDouble(next());
}
static char readCharacter () throws IOException {
return next().charAt(0);
}
static String readLine () throws IOException {
return br.readLine().trim();
}
}