Exercise 4.32

Explain the following loop.

constexpr int size = 5;
int ia[size] = {1, 2, 3, 4, 5};
for (int *ptr = ia, ix = 0; ix != size && ptr != ia+size; ++ix, ++ptr)
    ;   /* ... */

Solution

The loop will go through each element of ia with ptr and retain its subscript in ix.