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| 1 | +/// Given a binary tree, write a function to get the maximum width of the given tree. The maximum width of a tree is the maximum width among all levels. |
| 2 | +/// The width of one level is defined as the length between the end-nodes (the leftmost and right most non-null nodes in the level, where the null nodes between the end-nodes are also counted into the length calculation. |
| 3 | +/// |
| 4 | +/// It is guaranteed that the answer will in the range of 32-bit signed integer. |
| 5 | +/// |
| 6 | +/// Example 1: |
| 7 | +/// |
| 8 | +/// Input: |
| 9 | +/// |
| 10 | +/// 1 |
| 11 | +/// / \ |
| 12 | +/// 3 2 |
| 13 | +/// / \ \ |
| 14 | +/// 5 3 9 |
| 15 | +/// |
| 16 | +/// Output: 4 |
| 17 | +/// Explanation: The maximum width existing in the third level with the length 4 (5,3,null,9). |
| 18 | +/// Example 2: |
| 19 | +/// |
| 20 | +/// Input: |
| 21 | +/// |
| 22 | +/// 1 |
| 23 | +/// / |
| 24 | +/// 3 |
| 25 | +/// / \ |
| 26 | +/// 5 3 |
| 27 | +/// |
| 28 | +/// Output: 2 |
| 29 | +/// Explanation: The maximum width existing in the third level with the length 2 (5,3). |
| 30 | +/// Example 3: |
| 31 | +/// |
| 32 | +/// Input: |
| 33 | +/// |
| 34 | +/// 1 |
| 35 | +/// / \ |
| 36 | +/// 3 2 |
| 37 | +/// / |
| 38 | +/// 5 |
| 39 | +/// |
| 40 | +/// Output: 2 |
| 41 | +/// Explanation: The maximum width existing in the second level with the length 2 (3,2). |
| 42 | +/// Example 4: |
| 43 | +/// |
| 44 | +/// Input: |
| 45 | +/// |
| 46 | +/// 1 |
| 47 | +/// / \ |
| 48 | +/// 3 2 |
| 49 | +/// / \ |
| 50 | +/// 5 9 |
| 51 | +/// / \ |
| 52 | +/// 6 7 |
| 53 | +/// Output: 8 |
| 54 | +/// Explanation:The maximum width existing in the fourth level with the length 8 (6,null,null,null,null,null,null,7). |
| 55 | +/// |
| 56 | +/// |
| 57 | +/// Constraints: |
| 58 | +/// |
| 59 | +/// The given binary tree will have between 1 and 3000 nodes. |
| 60 | +/// |
| 61 | +/// 来源:力扣(LeetCode) |
| 62 | +/// 链接:https://leetcode-cn.com/problems/maximum-width-of-binary-tree |
| 63 | +/// 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 |
| 64 | +
|
| 65 | + |
| 66 | +use super::*; |
| 67 | + |
| 68 | +use std::collections::VecDeque; |
| 69 | +use std::cmp::max; |
| 70 | + |
| 71 | +struct Solution{} |
| 72 | +impl Solution { |
| 73 | + pub fn width_of_binary_tree(root: Option<Rc<RefCell<TreeNode>>>) -> i32 { |
| 74 | + |
| 75 | + let mut max_width = 0; |
| 76 | + let mut current_height = 0; |
| 77 | + let mut left = 0; |
| 78 | + let mut queue = VecDeque::new(); |
| 79 | + queue.push_front((root, 0, 0)); |
| 80 | + |
| 81 | + while !queue.is_empty() { |
| 82 | + match queue.pop_back() { |
| 83 | + Some((Some(n), pos, height) ) => { |
| 84 | + queue.push_front((RefCell::borrow(&n).left.clone(), pos * 2, height + 1)); |
| 85 | + queue.push_front((RefCell::borrow(&n).right.clone(), pos * 2 + 1, height + 1)); |
| 86 | + |
| 87 | + if current_height != height { |
| 88 | + current_height = height; |
| 89 | + left = pos |
| 90 | + } |
| 91 | + |
| 92 | + max_width = max(max_width, pos-left+1); |
| 93 | + }, |
| 94 | + _ => () |
| 95 | + } |
| 96 | + |
| 97 | + } |
| 98 | + |
| 99 | + max_width |
| 100 | + } |
| 101 | +} |
| 102 | + |
| 103 | +#[cfg(test)] |
| 104 | +mod tests { |
| 105 | + use super::*; |
| 106 | + |
| 107 | + #[test] |
| 108 | + fn test_1() { |
| 109 | + assert_eq!(Solution::width_of_binary_tree(tree!(1,2,3)), 2) |
| 110 | + } |
| 111 | +} |
| 112 | + |
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