Closed as not planned
Description
hello, I am very interested in the Zig language and am trying to master it, But I found an interesting phenomenon when I learned that function parameters may pass values or references.
Zig Version
0.15.0-dev.769+4d7980645
Test code
const std = @import("std");
const S = struct { val: u32 };
fn f(xa: *S, xb : S) void {
std.debug.print("before change: {} {*} {*}\n", .{xb.val, &xb.val, &xa.val});
xa.val = 20;
std.debug.print("after change: {} {*} {*}\n", .{xb.val, &xb.val, &xa.val});
}
pub fn main() void {
var x: S = .{ .val = 0 };
std.debug.print("in main: {} {*}\n", .{x.val, &x.val});
f(&x, x);
}#output:
in main: 0 u32@40835ff74c
before change: 0 u32@40835ff6dc u32@40835ff74c
after change: 20 u32@40835ff6dc u32@40835ff74c
#question:
Why do xa.val and xb.val have different addresses, but when I modify xa.val, the value of xb.val can be changed, Is there a problem with the way I get the address? Or some hidden magic that I don't know about?