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| 1 | +/** |
| 2 | + * 二分搜索树 |
| 3 | + */ |
| 4 | +class BST<T extends Comparable<T>> { |
| 5 | + _Node? root; |
| 6 | + |
| 7 | + int? size; |
| 8 | + |
| 9 | + BST() { |
| 10 | + root = null; |
| 11 | + size = 0; |
| 12 | + } |
| 13 | + |
| 14 | + int? getSize() { |
| 15 | + return size; |
| 16 | + } |
| 17 | + |
| 18 | + bool isEmpty() { |
| 19 | + return size == 0; |
| 20 | + } |
| 21 | + |
| 22 | + //添加元素 |
| 23 | +// add(T t) { |
| 24 | +// if (root == null) { |
| 25 | +// root = _Node(t); |
| 26 | +// size = size! + 1; |
| 27 | +// } else { |
| 28 | +// addNext(root, t); |
| 29 | +// } |
| 30 | +// } |
| 31 | + add(T e) { |
| 32 | + root = addNext(root, e); |
| 33 | + } |
| 34 | + |
| 35 | +// 向以node为根的二分搜索树中插入元素e,递归算法 |
| 36 | +// addNext(_Node? node, T? t) { |
| 37 | +// if (t! == node!.e) |
| 38 | +// return; |
| 39 | +// else if (t.compareTo(node.e) < 0 && node.left == null) { |
| 40 | +// node.left = _Node(t); |
| 41 | +// size = size! +1; |
| 42 | +// return; |
| 43 | +// } else if (t.compareTo(node.e) > 0 && node.right == null) { |
| 44 | +// node.right = _Node(t); |
| 45 | +// size = size! +1; |
| 46 | +// return; |
| 47 | +// } |
| 48 | +// if (t.compareTo(node.e) < 0) |
| 49 | +// addNext(node.left, t); |
| 50 | +// else //e.compareTo(node.e) > 0 |
| 51 | +// addNext(node.right, t); |
| 52 | +// } |
| 53 | + //返回新节点后二分搜索树的根 |
| 54 | + _Node addNext(_Node? node, T t) { |
| 55 | + if (node == null) { |
| 56 | + size = size! + 1; |
| 57 | + return _Node(t); |
| 58 | + } |
| 59 | + if (t.compareTo(node.e) < 0) { |
| 60 | + node.left = addNext(node.left, t); |
| 61 | + } else if (t.compareTo(node.e) > 0) { |
| 62 | + node.right = addNext(node.right, t); |
| 63 | + } |
| 64 | + return node; |
| 65 | + } |
| 66 | + |
| 67 | + // 向二分搜索树中添加新的元素e,非递归写法 |
| 68 | + add2(T e) { |
| 69 | + if (root == null) { |
| 70 | + root = _Node(e); |
| 71 | + size = size! + 1; |
| 72 | + return; |
| 73 | + } |
| 74 | + _Node? p = root; |
| 75 | + while (p != null) { |
| 76 | + if (e.compareTo(p.e) < 0) { |
| 77 | + if (p.left == null) { |
| 78 | + p.left = _Node(e); |
| 79 | + size = size! + 1; |
| 80 | + return; |
| 81 | + } |
| 82 | + p = p.left; |
| 83 | + } else if (e.compareTo(p.e) > 0) { |
| 84 | + if (p.right == null) { |
| 85 | + p.right = _Node(e); |
| 86 | + size = size! + 1; |
| 87 | + return; |
| 88 | + } |
| 89 | + p = p.right; |
| 90 | + } else |
| 91 | + return; |
| 92 | + } |
| 93 | + } |
| 94 | + |
| 95 | + //查询元素是否包含 |
| 96 | + bool contains(T t) { |
| 97 | + return _containsAll(root, t); |
| 98 | + } |
| 99 | + |
| 100 | + bool _containsAll(_Node? node, T t) { |
| 101 | + if (node == null) { |
| 102 | + return false; |
| 103 | + } |
| 104 | + if (t.compareTo(node.e) == 0) { |
| 105 | + return true; |
| 106 | + } else if (t.compareTo(node.e) < 0) { |
| 107 | + return _containsAll(node.left, t); |
| 108 | + } else { |
| 109 | + return _containsAll(node.right, t); |
| 110 | + } |
| 111 | + } |
| 112 | + |
| 113 | + // 二分搜索树的前序遍历 |
| 114 | + preOrder() { |
| 115 | + _preOrderDetail(root!); |
| 116 | + } |
| 117 | + |
| 118 | + _preOrderDetail(_Node? node) { |
| 119 | + if (node == null) { |
| 120 | + return; |
| 121 | + } |
| 122 | + print(node.e); |
| 123 | + _preOrderDetail(node.left); |
| 124 | + _preOrderDetail(node.right); |
| 125 | + } |
| 126 | + |
| 127 | + inOrder() { |
| 128 | + _inOrderDetail(root); |
| 129 | + } |
| 130 | + |
| 131 | + _inOrderDetail(_Node? node) { |
| 132 | + if (node == null) { |
| 133 | + return; |
| 134 | + } |
| 135 | + _inOrderDetail(node.left); |
| 136 | + print(node.e); |
| 137 | + _inOrderDetail(node.right); |
| 138 | + } |
| 139 | + |
| 140 | + postOrder() { |
| 141 | + _postOrderDetail(root); |
| 142 | + } |
| 143 | + |
| 144 | + _postOrderDetail(_Node? node) { |
| 145 | + if (node == null) { |
| 146 | + return; |
| 147 | + } |
| 148 | + _postOrderDetail(node.left); |
| 149 | + |
| 150 | + _postOrderDetail(node.right); |
| 151 | + print(node.e); |
| 152 | + } |
| 153 | + |
| 154 | + @override |
| 155 | + String toString() { |
| 156 | + StringBuffer res = new StringBuffer(); |
| 157 | + _generateBSTString(root!, 0, res); |
| 158 | + return res.toString(); |
| 159 | + } |
| 160 | + |
| 161 | + _generateBSTString(_Node? node, int depth, StringBuffer res) { |
| 162 | + if (node == null) { |
| 163 | + res.write("${_generateBSTStringDepth(depth)} null \n"); |
| 164 | + return; |
| 165 | + } |
| 166 | + res.write("${_generateBSTStringDepth(depth)} ${node.e} \n"); |
| 167 | + _generateBSTString(node.left, depth + 1, res); |
| 168 | + _generateBSTString(node.right, depth + 1, res); |
| 169 | + } |
| 170 | + |
| 171 | + _generateBSTStringDepth(int depth) { |
| 172 | + StringBuffer res = new StringBuffer(); |
| 173 | + for (int i = 0; i < depth; i++) { |
| 174 | + res.write(" - -"); |
| 175 | + } |
| 176 | + return res.toString(); |
| 177 | + } |
| 178 | +} |
| 179 | + |
| 180 | +class _Node<T> { |
| 181 | + T? e; |
| 182 | + |
| 183 | + _Node? left; |
| 184 | + |
| 185 | + _Node? right; |
| 186 | + |
| 187 | + _Node(T t) { |
| 188 | + this.e = t; |
| 189 | + this.left = null; |
| 190 | + this.right = null; |
| 191 | + } |
| 192 | +} |
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