solve problem Consecutive Numbers

Author: P-ppc

README.md

@@ -333,4 +333,5 @@ All solutions will be accepted!
 |181|[Employees Earning More Than Their Managers](https://leetcode-cn.com/problems/employees-earning-more-than-their-managers/description/)|[mysql](./database/EmployeesEarningMoreThanTheirManagers)|Easy|
 |176|[Second Highest Salary](https://leetcode-cn.com/problems/second-highest-salary/description/)|[mysql](./database/SecondHighestSalary)|Easy|
 |626|[Exchange Seats](https://leetcode-cn.com/problems/exchange-seats/description/)|[mysql](./database/ExchangeSeats)|Medium|
-|178|[Rank Scores](https://leetcode-cn.com/problems/rank-scores/description/)|[mysql](./database/RankScore)|Medium|
+|178|[Rank Scores](https://leetcode-cn.com/problems/rank-scores/description/)|[mysql](./database/RankScore)|Medium|
+|180|[Consecutive Numbers](https://leetcode-cn.com/problems/consecutive-numbers/description/)|[mysql](./database/ConsecutiveNumbers)|Medium|

database/ConsecutiveNumbers/README.md

@@ -0,0 +1,2 @@
+# Consecutive Numbers
+We can solve this problem by twice join

database/ConsecutiveNumbers/solution.sql

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+# Write your MySQL query statement below
+select distinct l.Num as ConsecutiveNums from Logs as l
+join Logs as r
+on l.Id + 1 = r.Id and l.Num = r.Num
+join Logs as r2
+on r.Id + 1 = r2.Id and r.Num = r2.Num