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added more problem loop related
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‎Easy-ones/Floor-Division.md

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## 1.4: Floor division
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**S-1: The problem**
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#### S-1: The problem
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Find the floor division of two numbers.
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<details>

‎Easy-ones/Math-Power.md

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## 1.2: Math Power
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**S-1: The problem**
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#### S-1: The problem
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Take two numbers from the users. Calculate the result of second number power of the first number.
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<details>

‎Easy-ones/Random-Number.md

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## 1.3: Create a random number
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**S-1: The problem**
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#### S-1: The problem
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Create a random number between 0 to 10
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<details>

‎Easy-ones/Temporary-variable.md

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## 1.5: Swap two variables
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**S-1: The problem**
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#### S-1: The problem
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> Swap two variables.<br><br>To swap two variables: the value of the first variable will become the value of the second variable. On the other hand, the value of the second variable will become the value of the first variable.
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<details>

‎Easy-ones/User-input-to-Number.md

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### 1.1: User input to Number
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**S-1: The problem**
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#### S-1: The problem
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Take two inputs from the user. One will be an integer. The other will be a float number. Then multiply them to display the output.
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<details>

‎Number-Related/Coin-sum.md ‎Loop-Related/Coin-sum.md

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‎Loop-Related/Largest-element-of-a-list.md

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## 3.2 Largest element of a list
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#### S-1: The problem
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Find the largest element of a list.
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<details>
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<summary><b>S-2: Click Here For Show Hints</b></summary>
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<p>Take the first element as the largest number. Then loop through the list and compare each element.
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</details>
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<br>
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#### S-3: Solution
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```python
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def get_largest(nums):
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largest = nums[0]
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for num in nums:
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if num > largest:
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largest = num
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return largest
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my_nums = [0,15,68,1,0,-55]
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largest = get_largest(my_nums)
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print('The largest number is: ', largest)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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#### S-4: Explanation
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In the beginning, consider the first element of the list as the largest element.
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Don’t set the largest value to 0. If every number in the list is a negative number, your return will be wrong.
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Then just loop through the list and compare. If the current number is greater than the largest number, set it as the largest number.
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That’s it. Easy peasy.
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#### S-5: Shortcut
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One shortcut is to pass a list of numbers to the max function. This will return the largest number in the list.
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```python
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nums = [41, 69, 23, 45, 19, 8]
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largest = max(nums)
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print(largest)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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#### S-6: Quiz
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What is the easiest way to find the largest number in a list?
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1. Use the max function
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2. Use the min function
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3. Use the sum function
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#### S-7: Take Away
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Use the max function to get the largest number in a list.
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&nbsp;
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[![Next Page](../assets/next-button.png)](Sum-of-squares.md)
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&nbsp;
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Loop-Related/Remove-duplicate-Chars.md

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‎Loop-Related/Second-Largest.md

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## 3.4 Second Largest
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#### S-1: The problem
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For a list, find the second largest number in the list.
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<details>
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<summary><b>S-2: Click Here For Show Hints</b></summary>
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<p>Finding the largest number was super easy. To find the second largest number, you have to keep track of two variables. Then compare.</p>
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</details>
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<br>
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#### S-3: Solution
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```python
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def get_second_largest(nums):
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largest = nums[0]
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second_largest = nums[0]
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for i in range(1,len(nums)):
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if nums[i] > largest:
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second_largest = largest
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largest = nums[i]
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elif nums[i] > second_largest:
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second_largest = nums[i]
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return second_largest
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my_nums = [44,11,83,29,25,76,88]
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second_largest = get_second_largest(my_nums)
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print("Second highest number is : ",second_largest)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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#### S-4: Explanation
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We declared two variables. One is called the largest. Another one is second_largest. We started both with the value of the first element of the list.
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Then we ran a for loop on range. The range looks like range(1, len(nums)). We started the list with 1 because we already set the first value as the largest and second_largest. Then the upper value of the range is len(nums).
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This means the range should run up to the length of the list.
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Inside the loop, we have an if-else block. If the current element num[ i ] greater than the current largest element. This means the current largest element will become the new second largest element. And the current element will become the largest element.
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On the other hand, if the current value is greater than the current second largest element, we just set the current value as the second largest element.
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That's it.
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#### S-5: Think Different
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Can you think about any way to solve this problem?
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One clever solution could be,
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Step 1: Use the max function to find the largest number.
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Step 2: Remove the max number from the list
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Step 3: From the remaining numbers, find the max number. As you already remove the previous max number, this max number will be the second-largest number.
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How cool is this solution?
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S-6: Clever Solution
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```python
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nums = [5, 12, 54, 87, 55, 69, 23, 17]
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nums.remove(max(nums))
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second_largest = max(nums)
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print(second_largest)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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The answer is:
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#### S-7: Take Away
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Clever ways to solve problems will make you happier.
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&nbsp;
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[![Next Page](../assets/next-button.png)](Second-smallest.md)
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&nbsp;
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Loop-Related/Second-smallest.md

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‎Loop-Related/Sum-of-squares.md

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## 3.3 Sum of squares
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#### S-1: The problem
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Take a number as input. Then get the sum of the numbers. If the number is n. Then get
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02+12+22+32+42+.............+n2
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<details>
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<summary><b>S-2: Click Here For Show Hints</b></summary>
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<p>Once again, run a for loop with a range. Inside the loop, use the power of 2. Then add that power to a sum variable. That’s it. </p>
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</details>
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<br>
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#### S-3: Solution
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```python
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def square_sum(num) :
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sum = 0
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for i in range(num+1) :
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square = (i ** 2)
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sum = sum + square
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return sum
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num = int(input('Enter a number: '))
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sum = square_sum(num)
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print('sum of square numbers is ', sum)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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#### S-4: Explanation
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This one is super easy. You declared a variable sum with an initial value 0.
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Then you run a for loop. This loop will run for range (num +1).
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The reason we are running it until num + 1. Because, we know that the range will stop just before the number inside it.
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For example, if we want to run the loop including 10. We should write 11 inside the range function.
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If needed, go to the code editor and run the following code.
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```python
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for i in range(10):
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print(i)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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And then run
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```python
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for i in range(11):
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print(i)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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#### S-5: Shortcut
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Sometimes there could be a better and easier way to solve a problem. For example, there is a simple math formula to calculate the sum of the square.
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This is the reason, you should search online and learn from different sources. This will make you stronger and better.
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If you want to calculate the sum of the square of n numbers, the formula is-
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n*(n+1)(2*n+1)/6
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Now you can use this formula.
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```python
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def sum_of_square2(n):
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sum = n*(n+1)*(2*n+1)/6
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return sum
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num = int(input('Enter a number: '))
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sum = sum_of_square2(num)
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print('Your sum of Square is: ', sum)
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```
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**[Try It:](/https://play.google.com/store/apps/details?id=com.learnprogramming.codecamp)**
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#### S-6: Quiz
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Why you should learn problem-solving from multiple sources?
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1. To utilize the internet bill correctly
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2. To learn alternative solutions
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3. To pretend that you are busy
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**The answer is: 2**
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#### S-7: Take Away
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Knowing shortcut ways will make you smarter and faster.
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&nbsp;
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[![Next Page](../assets/next-button.png)](Second-Largest.md)
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&nbsp;
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###### tags: `programmig-hero` `python` `float` `int` `math`
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‎Number-Related/Average-of-numbers.md

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## 2.3: Average of numbers
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**S-1: The problem**
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#### S-1: The problem
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Take numbers from a user and show the average of the numbers the user entered.
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<details>

‎Number-Related/Divisible-by-3-and-5.md

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## 2.4: Divisible by 3 and 5
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**S-1: The problem**
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#### S-1: The problem
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For a given number, find all the numbers smaller than the number. Numbers should be divisible by 3 and also by 5.
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<details>

‎Number-Related/Max-of-three.md

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## 2.2 max of three
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**S-1: The problem**
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#### S-1: The problem
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Find the largest of the three numbers.
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<details>

‎Number-Related/Sum-of-digits.md

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## 3.1: Sum of Elements
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**S-1: The problem**
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#### S-1: The problem
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For a given list, get the sum of each number in the list
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<details>
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Use the sum function to sum all the numbers in a list.
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&nbsp;
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[![Next Page](../assets/next-button.png)](../README.md)
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[![Next Page](../assets/next-button.png)](Coin-sum.md)
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&nbsp;
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###### tags: `programmig-hero` `python` `float` `int` `math`

‎Number-Related/max-of-two.md

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## 2.1 max of two
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**S-1: The problem**
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#### S-1: The problem
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Find the max number of two numbers.
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<details>

‎README.md

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* **[1.5](Easy-ones/Temporary-variable.md "Temporary variable")** - **[Temporary variable](/Easy-ones/Temporary-variable.md)**
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* **[2](Number-Relate/Number-Related.md "Number Related")** - &nbsp; **[Number Related](/Number-Related/Number-Related.md)**
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* **[2.1](Number-Relate "Max of two")** - **[Max of two](/Number-Relate)**
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* **[2.5](Number-Related/Sum-of-digits.md "Sum of digits")** - **[Sum of digits](Number-Related/Sum-of-digits.md)**
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* **[2.6](Number-Related/Coin-sum.md "Coin sum")** - **[Coin sum](Number-Related/Coin-sum.md)**
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* **[3](Loop-Relate/Coin-sum.md "Loop Related")** - &nbsp; **[Loop Related](/Number-Related/Coin-sum.md)**
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* **[3.1](Loop-Related/Coin-sum.md "Sum of elements")** - **[Sum of elements](Loop-Related/Coin-sum.md)**
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* **[3.2](Loop-Related/Largest-element-of-a-list.md "Largest element of a list")** - **[Largest element of a list](Loop-Related/Largest-element-of-a-list.md)**
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* **[3.3](Loop-Related/Sum-of-squares.md "Sum of squares")** - **[Sum of squares](Loop-Related/Sum-of-squares.md)**
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* **[3.4](Loop-Related/Second-Largest.md "Second Largest")** - **[Second Largest](Loop-Related/Second-Largest.md)**
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* **[3.5](Loop-Related/Second-smallest.md "Second Smallest")** - **[Second Smallest](Loop-Related/Second-smallest.md)**
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* **[3.6](Loop-Related/Remove-duplicate-Chars.md "Remove duplicate Chars")** - **[Remove duplicate Chars](Loop-Related/Remove-duplicate-Chars.md)**
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## 0: Introduction
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