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Contents.swift
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//: [上一道题](@previous)
/*:
# 插入区间
- 题号:[57](https://leetcode-cn.com/problems/insert-interval/)
- 难度:困难
- 描述:
给出一个**无重叠的**,按照区间起始端点排序的区间列表。
在列表中插入一个新的区间,你需要确保列表中的区间仍然有序且不重叠(如果有必要的话,可以合并区间)。
*/
//: ## Code
import Foundation
func insert(_ intervals: [[Int]], _ newInterval: [Int]) -> [[Int]] {
guard !intervals.isEmpty else { return [newInterval] }
guard !newInterval.isEmpty else { return intervals }
var result = intervals
let targetFirst = newInterval.first!
let targetLast = newInterval.last!
for i in 0 ..< intervals.count {
let interval = intervals[i]
let firt = interval.first!
let last = interval.last!
if targetFirst >= firt {
if targetFirst <= last {
// `newInterval` 被包含在这个区间范围内,直接终止循环
if targetLast <= last { break }
// 所要插入的区间的末尾,大于当前区间的末尾,但是小于下一区间的开头
if i >= intervals.count - 1 {
result[i] = [firt, targetLast]
} else {
let _tmp = intervals[i + 1].first!
if targetLast == _tmp {
result[i] = [firt, intervals[i + 1].last!]
result.remove(at: i + 1)
} else {
result[i] = [firt, targetLast]
}
}
break
}
if i >= intervals.count - 1 {
result.append(newInterval)
break
}
if targetLast < intervals[i + 1].first! {
result.insert(newInterval, at: i + 1)
break
}
} else {
if targetLast < firt {
result.insert(newInterval, at: i)
} else {
result[i] = [targetFirst, targetLast]
}
break
}
}
/* 最后的合并区间还没做 */
return result
}
//: ## Test
print(insert([[1,3],[6,9]], [7,10])) // [[1,3],[6,10]]
print(insert([[1,3],[6,9]], [2,6])) // [[1,9]]
print(insert([[1,3],[6,9]], [2,5])) // [[1,5],[6,9]]
print(insert([[1,3],[6,9]], [4,5])) // [[1,3],[4,5],[6,9]]
print(insert([[1,3],[6,9]], [10,11])) // [[1,3],[6,9],[10,11]]
print(insert([[1,2],[3,5],[6,7],[8,10],[12,16]], [4,8])) // [[1,2],[3,10],[12,16]]
//: [下一道题](@next)