-
Notifications
You must be signed in to change notification settings - Fork 47
Branches - Brianna K #30
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
base: master
Are you sure you want to change the base?
Conversation
CheezItMan
left a comment
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
Overall nice work, you hit the learning goals here. Well done. Check my comments below especially with regard to time/space complexity. Let me know if you have questions.
| # Space complexity: ? | ||
| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def factorial(n) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍
| temp_char = s[0] | ||
| s[0] = s[-1] | ||
| s[-1] = temp_char | ||
| return s[0] + reverse(s[1...-1]) + s[-1] |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
s[1..-1] creates a new array and copies all the individual elements over and so is O(n) by itself.
|
|
||
| # Time complexity: O(n/2) >> O(n) | ||
| # Space complexity: O(n) | ||
| def reverse(s) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍
This works, but because you create a new array with each recursive call this is O(n2) for both time/space complexity.
| # Space complexity: ? | ||
| # Time complexity: O(n/2) >> O(n) | ||
| # Space complexity: O(n) | ||
| def reverse_inplace(s) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
- This is not in place.
- This has similar time/space complexity to the above reverse... as in the exact same.
| # Space complexity: ? | ||
| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def bunny(n) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍
| # Space complexity: ? | ||
| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def nested(s) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍 This works, but you have similar time/space issues with the above methods.
| # Space complexity: ? | ||
| # Time complexity: O(n) - worst case | ||
| # Space complexity: O(n) - worst case | ||
| def search(array, value) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍 This works, but you have similar time/space issues with the above methods.
| # Space complexity: ? | ||
| # Time complexity: O(n/2) => O(n) | ||
| # Space complexity: O(n/2) => O(n) | ||
| def is_palindrome(s) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍 This works, but you have similar time/space issues with the above methods.
| # Space complexity: ? | ||
| # Time complexity: O(n) n is the length of the shortest array | ||
| # Space complexity: O(n) | ||
| def digit_match(n, m) |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍 Unusual approach, bu tit works.
No description provided.