Paper - Kaylyn #6
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CheezItMan
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Jan 11, 2022
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| def possible_bipartition(dislikes): | ||
| """ Will return True or False if the given graph | ||
| can be bipartitioned without neighboring nodes put | ||
| into the same partition. | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: O(NE) | ||
| Space Complexity: O(N) |
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👍 I do think however that the time complexity is O(N + E) because you hit every node and check each edge that node has, but you never repeat a node.
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SHE PUTS THE DONE IN CS FUN
WAIT
:) :)