Day 7: check a string's every even letter is uppercase, and every odd letter is lowercase.

Author: AimenYaseen

daily_challenges/day_7/1_matching_string.py

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+"""
+Define a function called myfunc that takes in a string,
+and returns a matching string where every even letter is uppercase,
+and every odd letter is lowercase.
+
+Desired output:
+myfunc('aNiMaL')-->True
+"""
+
+
+def matching_string(input_string):
+    even = ''
+    odd = ''
+
+    for i in range(len(input_string)):
+        if i % 2:
+            even += (input_string[i])
+        else:
+            odd += (input_string[i])
+
+    if odd.islower() and even.isupper():
+        return True
+    return False
+
+
+print(matching_string('aNiMaL'))
+print(matching_string('animal'))

daily_challenges/day_7/2_improved.py

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+def improved_matching_string(input_string):
+    odd = input_string[::2]
+    even = input_string[1::2]
+
+    if odd.islower() and even.isupper():
+        return True
+    return False
+
+
+print(improved_matching_string('aNiMaL'))
+print(improved_matching_string('animal'))

daily_challenges/day_7/3_short_form.py

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+# add two truth values it will give you 2
+_str = 'aNiMaLa'
+print((_str[0::2].islower() + _str[1::2].isupper()) == 2)

daily_challenges/day_7/4_complex_way.py

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+import re
+
+
+def matching_str():
+    word = 'aNiMaL'
+    func = lambda x: (x[0] % 2 == 0 and x[1].islower()) or (x[0] % 2 != 0 and x[1].isupper())
+    return len(word) == len(list(filter(func, list(enumerate(word)))))
+
+
+# using regex
+def myfunc(s):
+    return False if (len(s) == 0) else bool(re.fullmatch(r'([a-z][A-Z])*[a-z]?', s))