From 32236003042f36d43be6cd2022d799498bd78033 Mon Sep 17 00:00:00 2001
From: Bradley Nguyen <137482087+BradleyNgu@users.noreply.github.com>
Date: Sun, 27 Oct 2024 21:03:28 -0400
Subject: [PATCH] Update solution.md

change 2!/3^n to 1!/3^n as you'd get 14/3 as the answer and that makes no sense.
---
 src/content/questions/comp2804/2019-fall-midterm/10/solution.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/src/content/questions/comp2804/2019-fall-midterm/10/solution.md b/src/content/questions/comp2804/2019-fall-midterm/10/solution.md
index b3ae7867..03dfb784 100644
--- a/src/content/questions/comp2804/2019-fall-midterm/10/solution.md
+++ b/src/content/questions/comp2804/2019-fall-midterm/10/solution.md
@@ -8,7 +8,7 @@
 
 <ul>
     <li>$f(n) = 7 \cdot \frac{n!}{3^n}$ <br/>
-    $f(1) = 7 \cdot \frac{2!}{3^1} = 7 \cdot \frac{1}{3} = \frac{7}{3}$
+    $f(1) = 7 \cdot \frac{1!}{3^1} = 7 \cdot \frac{1}{3} = \frac{7}{3}$
     <li>$f(n) = 7^n \cdot \frac{n!}{3^n}$ <br/>
     $f(1) = 7^1 \cdot \frac{2!}{3^1} = 7 \cdot \frac{2}{3} = \frac{14}{3}$
     <li>$f(n) = 7 \cdot \frac{(n + 1)!}{3^n}$ <br/>