EXI for JSON in C programming language
C Makefile Other
Latest commit f8d5625 Mar 3, 2016 @danielpeintner danielpeintner fix issue #5



EXI for JSON in C programming language.

Note: source files in "src/exiforjson" and "src/json" are meant to show a mapping between textual JSON and EXIforJSON (and vice-versa). Constrained implementations are encouraged to use code in "src/codec" only by using the streaming API in a datatyped manner.

Build Status

Demo program

Sample program to illustrate how to write EXIforJSON and read JSON again

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#include "EXIforJSONEncoder.h"
#include "EXIforJSONDecoder.h"

#define BUFFER_SIZE 8192

int main(int argc, char *argv[]) {
    int errn = 0;

    char *JSON_STRING_IN = "{\"keyNumber\":   123, \"keyArrayStrings\": [ \"s1\", \"s2\" ] }";
    const size_t lenOut = strlen(JSON_STRING_IN) + 100; /* some extra space for decoding differences e.g, number 1 -> 1E0 etc */
    char JSON_STRING_OUT[lenOut];

    uint8_t buffer[BUFFER_SIZE];
    size_t posEncode = 0;
    size_t posDecode = 0;

    printf("FROM: \n%s \n", JSON_STRING_IN);

    errn = encodeEXIforJSON(JSON_STRING_IN, strlen(JSON_STRING_IN), buffer, BUFFER_SIZE, &posEncode);
    if( errn == 0 ) {
        /* OK so far */
        printf("Encoding JSON (len=%d) to EXIforJSON (len=%d) was successful \n", strlen(JSON_STRING_IN), posEncode);

        /* Try to transform it back to JSON again */
        errn = decodeEXIforJSON(buffer, BUFFER_SIZE, &posDecode, JSON_STRING_OUT, lenOut);

        if( errn == 0 ) {
            /* OK */
            printf("Decoding EXIforJSON (len=%d) to JSON (len=%d) was successful \n", posEncode, strlen(JSON_STRING_OUT));
            printf("TO: \n%s \n", JSON_STRING_OUT);
        } else {
            /* ERROR */
            printf("Decoding EXIforJSON to JSON failed due to error %d \n", errn);
    } else {
        /* ERROR */
        printf("Encoding JSON to EXIforJSON failed due to error %d \n", errn);

    return errn;