Question: Is it possible to define uuids() so that it only generates uuid4() ?

[subokita]

Is it possible to define uuids() so that it only generates uuid4() ?

Since I'm testing some other stuff, I'd like to have the generators only to create uuid4s.

[DRMacIver]

It isn't, but the UUID strategy isn't terribly complicated, and nor is the standard library code for generating uuid4s so it shouldn't be too hard to roll your own. Something like the following should work (I've not tested it though):

import hypothesis.strategies as st

@st.composite
def uuid4s(draw):
    rng = draw(st.shared(st.randoms(), key='hypothesis.strategies.uuids.generator'))
    return  UUID(int=rng.getrandbits(128), version=4)

A pull request adding UUID version support to hypothesis.strategies would be gratefully accepted if you wanted to make one. :-)

[Zac-HD]

A good first-time contribution:

• add a version=None keyword argument to hypothesis.strategies.uuids, and pass it through to the call to uuid.UUID.
• Raise InvalidArgument with a useful message if the version is not in (None, 1, 2, 3, 4, 5).
• Write a test that Hypothesis can generate UUIDS of each allowed version.