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parserLanguage parsing and surface syntaxLanguage parsing and surface syntax
Description
Julia appears not to recognise for outer constructions in Expressions when performing substitution. This has been tested using Julia 1.2 and 1.5.1.
The following snippet without outer works as expected, substituting the value :p into the for loop:
julia> g() = begin
q = :p
:(for $q = 1:2:3 end)
end
g (generic function with 1 method)
julia> g()
:(for p = 1:2:3
end)
However, when outer is added the variable substitution is not recognised:
julia> f() = begin
q = :p
:(for outer $q = 1:2:3 end)
end
f (generic function with 1 method)
julia> f()
:(for outer $ q = 1:2:3
end)
Julia version info:
Julia Version 1.5.1
Commit 697e782ab8 (2020-08-25 20:08 UTC)
Platform Info:
OS: Linux (x86_64-pc-linux-gnu)
CPU: Intel(R) Core(TM) i5-5300U CPU @ 2.30GHz
WORD_SIZE: 64
LIBM: libopenlibm
LLVM: libLLVM-9.0.1 (ORCJIT, broadwell)
Environment:
JULIA_PATH = /usr/local/julia
JULIA_GPG = 3673DF529D9049477F76B37566E3C7DC03D6E495
JULIA_VERSION = 1.5.1
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parserLanguage parsing and surface syntaxLanguage parsing and surface syntax