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600eebb @smenks13 New exercise: Completing the square 1
smenks13 authored
1 <!DOCTYPE html>
2 <html data-require="math polynomials expressions math-format">
3 <head>
4e4cb9b @beneater lint: tabs->spaces and jQuery->$ for exercises
beneater authored
4 <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
5 <title>Completing the square 1</title>
6 <script src="../khan-exercise.js"></script>
7 <style type="text/css">
8 #answer_area .short input[type=text] {
9 width: 60px;
10 }
11 </style>
600eebb @smenks13 New exercise: Completing the square 1
smenks13 authored
12 </head>
13 <body>
4e4cb9b @beneater lint: tabs->spaces and jQuery->$ for exercises
beneater authored
14 <div class="exercise">
15 <div class="problems">
16 <div id="original" data-weight="5">
17 <div class="vars">
18 <var id="X1">randRangeNonZero( -10, 10 )</var>
19 <var id="X2" data-ensure="X1 !== X2">randRange( -5, 5 ) * 2 + ( X1 % 2 )</var>
20 <var id="B">( X1 + X2 ) * -1</var>
21 <var id="C">X1 * X2</var>
22 <var id="POLY">new Polynomial( 0, 2, [C, B, 1], "x" )</var>
23 <var id="POLY_TEXT">POLY.text()</var>
24 </div>
25 <p class="question">Solve for <code>x</code> by completing the square.</p>
26 <p><code><var>POLY_TEXT</var> = 0</code></p>
27 <div class="solution" data-type="set">
28 <div class="set-sol"><var>X1</var></div>
29 <div class="set-sol"><var>X2</var></div>
30 <div class="input-format">
31 <p><code>x = \quad</code><span class="entry short"></span><code>\quad \text{or} \quad x = \quad</code><span class="entry short"></span></p>
32 </div>
33 </div>
34 </div>
35 <div id="one-root" data-type="original" data-weight="1">
36 <div class="vars">
37 <var id="X2">X1</var>
38 </div>
39 <div class="solution" data-type="multiple">
40 <p><code>x = \quad</code><span class="sol"><var>X1</var></span></p>
41 </div>
42 </div>
43 </div>
44 <div class="hints">
45 <div data-if="X1 !== X2" data-unwrap>
46 <div data-if="C !== 0">
47 <p>Begin by moving the constant term to the right side of the equation.</p>
48 <p><code>x^2 <span data-if="B !== 0"> + <var>B</var>x</span> = <var>C * -1</var></code></p>
49 </div>
50 <div data-if="B !== 0">
51 <p>We complete the square by taking half of the coefficient of our <code>x</code> term, squaring it, and adding it to both sides of the equation. Since the coefficient of our <code>x</code> term is <code><var>B</var></code>, half of it would be <code><var>B / 2</var></code>, and squaring it gives us <code>\color{blue}{<var>pow( B / 2, 2 )</var>}</code>.</p>
52 <p><code>x^2 + <var>B</var>x \color{blue}{ + <var>pow( B / 2, 2 )</var>} = <var>C * -1</var> \color{blue}{ + <var>pow( B / 2, 2 )</var>}</code></p>
53 </div>
54 <div data-if="B !== 0">
55 <p>We can now rewrite the left side of the equation as a squared term.</p>
56 <p><code>( x + <var>B / 2</var> )^2 = <var>C * -1 + pow( B / 2, 2 )</var></code></p>
57 </div>
58 </div>
59 <div data-else data-unwrap>
60 <p>The left side of the equation is already a perfect square trinomial. The coefficient of our <code>x</code> term is <code><var>B</var></code>, half of it is <code><var>B / 2</var></code>, and squaring it gives us <code>\color{blue}{<var>pow( B / 2, 2 )</var>}</code>, our constant term.</p>
61 <div>
62 <p>Thus, we can rewrite the left side of the equation as a squared term.</p>
63 <p><code>( x + <var>B / 2</var> )^2 = <var>C * -1 + pow( B / 2, 2 )</var></code></p>
64 </div>
65 </div>
66 <div>
67 <p>Take the square root of both sides.</p>
68 <p><code>x <span data-if="B !== 0"> + <var>B / 2</var></span> = <span data-if="sqrt( C * -1 + pow( B / 2, 2 ) ) !== 0">\pm</span><var>sqrt( C * -1 + pow( B / 2, 2 ) )</var></code></p>
69 </div>
70 <div data-if="B !== 0">
71 <p>Isolate <code>x</code> to find the solution(s).</p>
72 <p data-if="sqrt( C * -1 + pow( B / 2, 2 ) ) !== 0"><code>x = <var>-B / 2</var>\pm<var>sqrt( C * -1 + pow( B / 2, 2 ) )</var></code></p>
73 <p><code>x = <var>-B / 2 + sqrt( C * -1 + pow( B / 2, 2 ) )</var><span data-if="sqrt( C * -1 + pow( B / 2, 2 ) ) !== 0"> \text{ or } x = <var>-B / 2 - sqrt( C * -1 + pow( B / 2, 2 ) )</var></span></code></p>
74 </div>
75 <div data-else>
76 <p><code>x = <var>-B / 2 + sqrt( C * -1 + pow( B / 2, 2 ) )</var><span data-if="sqrt( C * -1 + pow( B / 2, 2 ) ) !== 0"> \text{ or } x = <var>-B / 2 - sqrt( C * -1 + pow( B / 2, 2 ) )</var></span></code></p>
77 </div>
78 </div>
79 </div>
600eebb @smenks13 New exercise: Completing the square 1
smenks13 authored
80 </body>
c2cb4db @spicyj Whitespace :)
spicyj authored
81 </html>
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