# Khan/khan-exercises

Add new exercise: area of parallelograms.

1 parent 22d4ca2 commit a46a295d70ce1ff3dd3d571a23e773cdf2b64313 osnr committed Jun 28, 2012
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+ randFromArray([ + ["in", "inch"], + ["ft", "foot"], + ["m", "meter"], + ["cm", "centimeter"], + ["", "unit"] + ]) + + randRange(1, 8) + randRange(1, 8) + + randRangeNonZero(-2, 2) + + B * H +
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Suppose a parallelogram has base length B \text{ UNIT} and height H \text{ UNIT}.
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What is the parallelogram's area?
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+ K + square plural(UNIT_TEXT) +
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+ graph.p = parallelogram(B, H, UNIT, SH); + + graph.p.drawBase(); + graph.p.drawHeight(); +
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By moving a slice of the parallelogram, we can see that its area is equal to that of a rectangle with the same base and height.

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+ graph.p.sliceHint(); + graph.p.animHint(); +
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area of rectangle = b \times h

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+ graph.p.drawArea(); +
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A = B \times H = K

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