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commit daa0b218535e79402bdc09fca233e3e411f0487b 1 parent 8d21c48
@petercollingridge petercollingridge authored
Showing with 7 additions and 7 deletions.
  1. +7 −7 exercises/dividing_polynomials_by_binomials_2.html
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14 exercises/dividing_polynomials_by_binomials_2.html
@@ -18,11 +18,11 @@
<var id="C">randRangeNonZero( -10, 10 )</var>
</div>
<var id="SQUARE">1</var>
- <var id="CONSTANT">SQUARE*A*B</var>
- <var id="SIMPLECONSTANT">A*B</var>
- <var id="LINEAR">SQUARE*(-A-B)</var>
- <var id="SIMPLELINEAR">-A-B</var>
- <var id="SOLUTIONCONSTANT">-C*B</var>
+ <var id="CONSTANT">SQUARE * A * B</var>
+ <var id="SIMPLECONSTANT">A * B</var>
+ <var id="LINEAR">SQUARE * (-A - B)</var>
+ <var id="SIMPLELINEAR">-A - B</var>
+ <var id="SOLUTIONCONSTANT">C * -B</var>
</div>
<p class="problem">Simplify the following expression:</p>
@@ -39,12 +39,12 @@
<p>First factor the polynomial in the numerator.</p>
<div>
- <p>We can factor out a <code><var>C</var></code> from the numerator:</p>
+ <p>We we notice that all the terms in the numerator have a common factor of <code><var>C</var></code>, so we can rewrite the expression:</p>
<p><code>\dfrac{<var>C</var>(<var>plus(SQUARE + "x^2")</var> + <var>plus(LINEAR + "x" )</var> + <var>CONSTANT</var>)}{x + <var>-A</var>}</code></p>
</div>
<div>
- <p>We then factor the remaining polynomial:</p>
+ <p>Then we factor the remaining polynomial:</p>
<p><code>
x^2 <var>SIMPLELINEAR &gt;= 0 ? "+" : ""</var> <var>plus( "\\color{" + GREEN + "}{" + SIMPLELINEAR + "}x" )</var>
<var>SIMPLECONSTANT &gt;= 0 ? "+" : ""</var> <var>plus( "\\color{" + BLUE + "}{" + SIMPLECONSTANT + "}" )</var>
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