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change hint in graphing systems of inequalities 2 to be hopefully les…

…s misleading

Reviewers: eater

Reviewed By: eater

Differential Revision: http://phabricator.khanacademy.org/D644
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1 parent cd99279 commit e66dea6ef60fb264ad8e13f34da65ad8c8b20d33 @mwittels mwittels committed Aug 15, 2012
Showing with 4 additions and 5 deletions.
  1. +4 −5 exercises/graphing_systems_of_inequalities_2.html
@@ -510,10 +510,11 @@
</div>
<div>
<p>
- Plot each of the points to determine which are solutions:
- <code class="hint_pink">(<var>POINT_1[0]</var>, <var>POINT_1[1]</var>)</code> and
- <code class="hint_pink">(<var>POINT_2[0]</var>, <var>POINT_2[1]</var>)</code>
+ To determine if a point is a solution to <b>both</b> inequalities, plot it on the
+ graph and see if it lies within <b>both</b> shaded areas.
</p>
+ </div>
+ <div>
<div class="graphie" data-update="grid">
style({ stroke: PINK, fill: PINK }, function() {
circle( POINT_1, 0.2 ).toBack();
@@ -522,8 +523,6 @@
label( POINT_2, "\\color{" + PINK + "}{(" + POINT_2[0] + ", " + POINT_2[1] + ")}", "right" );
});
</div>
- </div>
- <div>
<p data-if="POINT_1_SOLUTION && !POINT_2_SOLUTION">
<code class="hint_pink">(<var>POINT_1[0]</var>, <var>POINT_1[1]</var>)</code> is a solution because it's inside both shaded areas, but
<code class="hint_pink">(<var>POINT_2[0]</var>, <var>POINT_2[1]</var>)</code> is not.

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