# Khan/khan-exercises

Format text properly

1 parent db63b02 commit f688a1867b19c414b9bc9a1020f15431818d2bad petercollingridge committed Mar 25, 2013
Showing with 7 additions and 7 deletions.
1. +7 −7 exercises/rate_problems_1.html
14 exercises/rate_problems_1.html
 @@ -50,7 +50,7 @@ So he(1) traveled SPEED1 \times \frac{T1[0]}{T1[1]} T1[0] - = plural(round(DIST1), "\\space mile") by vehicle(1). + = round(DIST1) miles by vehicle(1).

@@ -71,7 +71,7 @@ So he(1) traveled SPEED2 \times \frac{T2[0]}{T2[1]} T2[0] - = plural(round(DIST2), "\\space mile") by vehicle(2). + = round(DIST2) miles by vehicle(2).

@@ -107,7 +107,7 @@
-

Remember that distance = speed \times time.

+

Remember that \text{distance} = \text{speed} \times \text{time}.

Call the time that person(1) traveled by vehicle(1), t.

@@ -142,18 +142,18 @@ label([ 2.6, 0.5 ], "t", "above", {color: RED}); label([ 7.6, 0.5 ], TIME + " - t", "above", {color: BLUE}); - label([ 5.1, 0.5 ], TIME + "\\space hours", "below"); + label([ 5.1, 0.5 ], TIME + "\\space \\text{hours}", "below");
-

person(1) traveled at SPEED1 \frac{miles}{hour} for +

person(1) traveled at SPEED1 \frac{ \text{miles} }{ \text{hour} } for t hours by vehicle(1).

Therefore, he(1) traveled SPEED1t miles by vehicle(1).
-

person(1) traveled at SPEED2 \frac{miles}{hour} for +

person(1) traveled at SPEED2 \frac{ \text{miles} }{ \text{hour} } for TIME - t hours by vehicle(2).

Therefore, he(1) traveled SPEED2 (TIME - t) miles by vehicle(2).
@@ -192,7 +192,7 @@ label([ 2.6, 0.5 ], SPEED1 + "t", "above", {color: RED}); label([ 7.6, 0.5 ], SPEED2 + "(" + TIME + " - t)", "above", {color: BLUE}); - label([ 5.1, 0.5 ], DIST + "\\space miles", "below"); + label([ 5.1, 0.5 ], DIST + "\\space \\text{miles}", "below");