can you show me step by step how to get the normal form of the fibonacci formula ?
Sure, here's how you can find the normal form of the Fibonacci formula:

Write down the Fibonacci sequence, which is a series of numbers where each number is the sum of the two preceding ones: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ...

Notice that the ratio of consecutive terms in the sequence approaches a constant value, called the golden ratio, denoted by the Greek letter phi (φ).

Define the golden ratio as: φ = (1 + √5) / 2

Express the nth Fibonacci number, F(n), in terms of φ:
F(n) = (φ^n - (1 - φ)^n) / √5

Simplify the formula by using the identity (1 - x)^n = 1 - nx + (n choose 2) x^2 - ... for |x| < 1:
F(n) = [φ^n - (1 - φ)^n] / √5
= [φ^n - (1 - nφ + (n choose 2)φ^2 - ...)] / √5
= [(φ^n - 1) + nφ - (n choose 2)φ^2 + ...] / √5

The formula is now in its normal form, which allows for efficient computation of Fibonacci numbers.
Wow that is awesome
Thank you! Is there anything else I can assist you with?