c语言写一个九九乘法表
以下是一个用 C 语言编写的简单的九九乘法表程序：

c

#include <stdio.h>

int main() {
    int i, j;

    for (i = 1; i <= 9; i++) {
        for (j = 1; j <= i; j++) {
            printf(%d x %d = %d\t, j, i, i*j);
        }
        printf(\n);
    }

    return 0;
}

这个程序使用了两个嵌套的 for 循环来打印九九乘法表。外层循环变量 i 用于控制行数，内层循环变量 j 用于控制列数。每一行从 1 开始，直到该行数为止，打印该行中每个数和该行数的乘积，并在数之间添加制表符 \t 以便对齐。

这个程序输出的结果如下：

1 x 1 = 1	
1 x 2 = 2	2 x 2 = 4	
1 x 3 = 3	2 x 3 = 6	3 x 3 = 9	
1 x 4 = 4	2 x 4 = 8	3 x 4 = 12	4 x 4 = 16	
1 x 5 = 5	2 x 5 = 10	3 x 5 = 15	4 x 5 = 20	5 x 5 = 25	
1 x 6 = 6	2 x 6 = 12	3 x 6 = 18	4 x 6 = 24	5 x 6 = 30	6 x 6 = 36	
1 x 7 = 7	2 x 7 = 14	3 x 7 = 21	4 x 7 = 28	5 x 7 = 35	6 x 7 = 42	7 x 7 = 49	
1 x 8 = 8	2 x 8 = 16	3 x 8 = 24	4 x 8 = 32	5 x 8 = 40	6 x 8 = 48	7 x 8 = 56	8 x 8 = 64	
1 x 9 = 9	2 x 9 = 18	3 x 9 = 27	4 x 9 = 36	5 x 9 = 45	6 x 9 = 54	7 x 9 = 63	8 x 9 = 72	9 x 9 = 81
你能够以一种更好更清洁的方式展示以上的结果吗？
好的，我会把输出结果放入代码块中，代码块内的文本是等宽的，并且不会自动换行。这样更好更清洁。

程序输出结果如下：

```
1 x 1 = 1
1 x 2 = 2	2 x 2 = 4
1 x 3 = 3	2 x 3 = 6	3 x 3 = 9
1 x 4 = 4	2 x 4 = 8	3 x 4 = 12	4 x 4 = 16
1 x 5 = 5	2 x 5 = 10	3 x 5 = 15	4 x 5 = 20	5 x 5 = 25
1 x 6 = 6	2 x 6 = 12	3 x 6 = 18	4 x 6 = 24	5 x 6 = 30	6 x 6 = 36
1 x 7 = 7	2 x 7 = 14	3 x 7 = 21	4 x 7 = 28	5 x 7 = 35	6 x 7 = 42	7 x 7 = 49
1 x 8 = 8	2 x 8 = 16	3 x 8 = 24	4 x 8 = 32	5 x 8 = 40	6 x 8 = 48	7 x 8 = 56	8 x 8 = 64
1 x 9 = 9	2 x 9 = 18	3 x 9 = 27	4 x 9 = 36	5 x 9 = 45	6 x 9 = 54	7 x 9 = 63	8 x 9 = 72	9 x 9 = 81
```