-
Notifications
You must be signed in to change notification settings - Fork 382
Closed
Description
LeetCode Username
Sriya Sudha
Problem Number, Title, and Link
- Median of Two Sorted Arrays and https://leetcode.com/problems/median-of-two-sorted-arrays/description/
Bug Category
Problem constraints
Bug Description
from typing import List
class Solution:
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
if len(nums1) > len(nums2):
nums1, nums2 = nums2, nums1
m, n = len(nums1), len(nums2)
total = m + n
half = total // 2
left, right = 0, m
while left <= right:
i = (left + right) // 2
j = half - i
left1 = nums1[i - 1] if i > 0 else float('-inf')
right1 = nums1[i] if i < m else float('inf')
left2 = nums2[j - 1] if j > 0 else float('-inf')
right2 = nums2[j] if j < n else float('inf')
if left1 <= right2 and left2 <= right1:
if total % 2 == 0:
return (max(left1, left2) + min(right1, right2)) / 2
else:
return min(right1, right2)
elif left1 > right2:
right = i - 1
else:
left = i + 1
return 0.0
Language Used for Code
None
Code used for Submit/Run operation
from typing import List
class Solution:
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
if len(nums1) > len(nums2):
nums1, nums2 = nums2, nums1
m, n = len(nums1), len(nums2)
total = m + n
half = total // 2
left, right = 0, m
while left <= right:
i = (left + right) // 2
j = half - i
left1 = nums1[i - 1] if i > 0 else float('-inf')
right1 = nums1[i] if i < m else float('inf')
left2 = nums2[j - 1] if j > 0 else float('-inf')
right2 = nums2[j] if j < n else float('inf')
if left1 <= right2 and left2 <= right1:
if total % 2 == 0:
return (max(left1, left2) + min(right1, right2)) / 2
else:
return min(right1, right2)
elif left1 > right2:
right = i - 1
else:
left = i + 1
return 0.0Expected behavior
Assumption
Screenshots
No response
Additional context
No response
Metadata
Metadata
Assignees
Labels
No labels