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CSAW CTF Qualification Round 2019 : Count On Me

category : crypto

points : 400

solves : 108

write-up

TEST_CRT_encrypt can be simplified to

for arbitrary k, m is fake flag
c = c2 + q * (qinv * (c1 - c2) % p)
c = c2 + (kp + q % p) * (qinv * (c1 - c2) % p)
c = c2 + ((c1 - c2) % p) + kp
c = c1 % p + kp
c = m ** e % p + kp

So we know that gcd(n, m ** e - c) = kp

x, y are generated from gen_prime offset, and is very small

Finally, brute force against the fake flag and factor n using gcd

flag: flag{ooo000_f4ul7y_4nd_pr3d1c74bl3_000ooo}

other write-ups and resources