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.. operator #981
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From ashted@southern.edubash$ cat x for (1) { bash$ perl -V Characteristics of this binary (from libperl): Thanks, |
From @tamiasOn Tue, Dec 21, 1999 at 12:31:43PM -0500, Ted Ashton wrote:
Yes. perldoc perlop: If either operand of scalar ".." is a 1 is a constant expression. $_ is not. Ronald |
From [Unknown Contact. See original ticket]
What you're missing is that $. never went ==1. In the --tom |
Migrated from rt.perl.org#1929 (status was 'resolved')
Searchable as RT1929$
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