Hopefully clarify that Perl 6 doesn't have references better

doc/Language/5to6-nutshell.pod6

@@ -443,17 +443,19 @@ so we will have to focus on the intent of the reference operators
 instead of the actual syntax.
 
 =for code :lang<perl5>
-my $aref =     \@aaa  ; # Perl 5
+my $aref = \@aaa  ; # Perl 5
 
-This might be used for passing a reference to a routine, for instance. But in Perl 6, the default behavior is a pass by reference.
+This might be used for passing a reference to a routine, for instance. But in
+Perl 6, the (single) underlying object is passed (which you could consider
+to be a sort of pass by reference).
 
 =begin code
-my @a = 4,8,15;
-(-> @array { @array[0] = 66})(@a);
-say @a; #  OUTPUT: «[66 8 15]␤»
+my @array = 4,8,15;
+{ $_[0] = 66 }(@array);   # run the block with @array aliased to $_
+say @array; #  OUTPUT: «[66 8 15]␤»
 =end code
 
-The declared C<@a> is passed by reference, and its first value modified inside the declared routine.
+The underlying Array object of C<@array> is passed, and its first value modified inside the declared routine.
 
 In Perl 5, the syntax for dereferencing an entire reference is the
 type-sigil and curly braces, with the reference inside the curly braces. In Perl 6, this concept simply does not apply, since the I<reference> metaphor does not really apply.