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[euler] solution for problem 65
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andreoss committed May 19, 2015
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69 changes: 69 additions & 0 deletions categories/euler/prob065-andreoss.pl
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#!/usr/bin/env perl6
use v6;

=begin pod
=TITLE Square root digital expansion
=AUTHOR Andrei Osipov
L<https://projecteuler.net/problem=65>
The square root of 2 can be written as an infinite continued fraction.
√2 = 1 + 1
______
2 + 1
______
2 + 1
______
2 + 1
______
2 + ...
The infinite continued fraction can be written, √2 = [1;(2)], (2) indicates that
2 repeats ad infinitum. In a similar way, √23 = [4;(1,3,1,8)].
It turns out that the sequence of partial values of continued fractions for square
roots provide the best rational approximations. Let us consider the convergents for √2.
1 + 1
___ = 3/2
2
1 + 1
_________ = 7/5
2 + 1 / 2
....
Hence the sequence of the first ten convergents for √2 are:
1, 3/2, 7/5, 17/12, 41/29, 99/70, 239/169, 577/408, 1393/985, 3363/2378, ...
What is most surprising is that the important mathematical constant,
e = [2; 1,2,1, 1,4,1, 1,6,1 , ... , 1,2k,1, ...].
The first ten terms in the sequence of convergents for e are:
2, 3, 8/3, 11/4, 19/7, 87/32, 106/39, 193/71, 1264/465, 1457/536, ...
The sum of digits in the numerator of the 10th convergent is 1+4+5+7=17.
Find the sum of digits in the numerator of the 100th convergent of the continued fraction for e.
Expected result: 272
=end pod

sub continued-fraction(@sequence, :$depth) {
my $x = @sequence.shift;
return 1 if $depth == 1;
$x + 1.FatRat /
continued-fraction :depth($depth - 1), @sequence
}

my @e := gather { take 2; take (1; $_; 1) for 2,4 ... * };

say [+] continued-fraction(@e, depth => 100).numerator.comb;
2 changes: 1 addition & 1 deletion categories/euler/prob080-andreoss.pl
Expand Up @@ -4,7 +4,7 @@
=TITLE Square root digital expansion
=AUTHOR Your name (or nick, if you want)
=AUTHOR Andrei Osipov
L<https://projecteuler.net/problem=80>
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8 changes: 8 additions & 0 deletions t/categories/euler.t
Expand Up @@ -396,7 +396,15 @@ subtest {

check-example-solutions($problem, $expected-output, @authors)
}, "prob063";
subtest {
plan 1;

my $problem = "prob065";
my @authors = <andreoss>;
my $expected-output = 272;

check-example-solutions($problem, $expected-output, @authors)
}, "prob065";
subtest {
plan 1;

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