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:i modifier precedence on alternations #2031

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p6rt opened this issue Aug 7, 2010 · 5 comments
Closed

:i modifier precedence on alternations #2031

p6rt opened this issue Aug 7, 2010 · 5 comments

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@p6rt
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@p6rt p6rt commented Aug 7, 2010

Migrated from rt.perl.org#77064 (status was 'resolved')

Searchable as RT77064$

@p6rt
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@p6rt p6rt commented Aug 7, 2010

From oha@oha.it

i expected that both the following should fails​:

say 'X' if 'bar' ~~ /​:i FOO || BAR/; # only FOO modified by :i
say 'Y' if 'Y' ~~ /​:i || FOO || BAR/; # i expected the first alternation
empty (and skipped then)

and i expected the following to match, but isn't​:

say 'Z' if 'Ab' eq 'Ab' ~~ / A :i B || C /

@p6rt
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@p6rt p6rt commented Nov 13, 2011

From @coke

On Sat Aug 07 02​:43​:43 2010, oha.it wrote​:

i expected that both the following should fails​:

say 'X' if 'bar' ~~ /​:i FOO || BAR/; # only FOO modified by :i
say 'Y' if 'Y' ~~ /​:i || FOO || BAR/; # i expected the first alternation
empty (and skipped then)

and i expected the following to match, but isn't​:

say 'Z' if 'Ab' eq 'Ab' ~~ / A :i B || C /

Some more recent output​:

19​:06 <@​Coke> nom​: say 'X' if 'bar' ~~ /​:i FOO || BAR/;
19​:06 <+p6eval> nom ef4702​: ( no output )
19​:07 <@​Coke> nom​: say 'X' if 'BAR' ~~ /​:i FOO || BAR/;
19​:07 <+p6eval> nom ef4702​: OUTPUT«X␤»
19​:07 <@​Coke> nom​: say 'X' if 'foo' ~~ /​:i FOO || BAR/;
19​:07 <+p6eval> nom ef4702​: ( no output )
19​:08 <@​Coke> nom​: say 'Z' if 'Ab' eq 'Ab' ~~ / A :i B || C /
19​:08 <+p6eval> nom ef4702​: ( no output )

--
Will "Coke" Coleda

@p6rt
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@p6rt p6rt commented Nov 13, 2011

The RT System itself - Status changed from 'new' to 'open'

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@p6rt p6rt commented Jan 1, 2015

From @moritz

Hi,

On Sat Aug 07 02​:43​:43 2010, oha.it wrote​:

i expected that both the following should fails​:

say 'X' if 'bar' ~~ /​:i FOO || BAR/; # only FOO modified by :i
say 'Y' if 'Y' ~~ /​:i || FOO || BAR/; # i expected the first alternation
empty (and skipped then)

I regret to inform you that your expectations aren't backed by S05; it indicates that :i is lexically scoped, and that subrules and [] and () introduce lexical scopes; I see no indication that || introduces lexical scopes.

and i expected the following to match, but isn't​:

say 'Z' if 'Ab' eq 'Ab' ~~ / A :i B || C /

Assuming the eq is a mistake, this has now been fixed (by NQP commit b924e932). (It was an over-eager optimization that concatenated consecutive literals, and didn't check whether :i changed for them)

Cheers,
Moritz

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@p6rt p6rt commented Jan 1, 2015

@moritz - Status changed from 'open' to 'resolved'

@p6rt p6rt closed this Jan 1, 2015
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