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The optional $_ seems to default to $CALLER::_, not $OUTER::_ in Rakudo #2216

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p6rt opened this issue Oct 7, 2010 · 3 comments
Open

The optional $_ seems to default to $CALLER::_, not $OUTER::_ in Rakudo #2216

p6rt opened this issue Oct 7, 2010 · 3 comments
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@p6rt
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@p6rt p6rt commented Oct 7, 2010

Migrated from rt.perl.org#78278 (status was 'open')

Searchable as RT78278$

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@p6rt p6rt commented Oct 7, 2010

From @masak

<tylercurtis> Actually, maybe { /O/ } should be -> $_? { /O/ }
<masak> it is.
<masak> rakudo​: my $b = { /O/ }; say $b.signature.count; say $b.signature.arity
<p6eval> rakudo 377615​: OUTPUT«1␤0␤»
<jnthn> I'ts more like -> $_ = $OUTER​::_ I guess
<masak> fair enuf.
<tylercurtis> Well, yes, that.
<masak> OUTER, and not CALLER?
<masak> rakudo​: my $b; { $_ = 5; $b = { .say } }; $_ = 42; $b()
<p6eval> rakudo 377615​: OUTPUT«42␤»
<masak> seems to me $_ defaults to $CALLER​::_
* masak submits rakudobug
<tylercurtis> How does that distinguish between $OUTER​::_ and
$CALLER​::_? The calling scope is the same as the outer scope, no?
<masak> no, the outer scope has $_ = 5, but the calling scope has $_ = 42
<jnthn> rakudo​: my $b; { my $_ = 5; $b = { .say } }; $_ = 42; $b()
<p6eval> rakudo 377615​: OUTPUT«5␤»

jnthn says that the problem is that there's a binding to the outer
container rather than an assignment, and that the last evaluation
shows this.

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@p6rt p6rt commented Apr 7, 2016

From @diakopter

new behavior​:

12​:18 <diakopter> m​: my $b; { my $_ = 5; $b = { .say } }; $_ = 42; $b()
12​:18 <camelia> rakudo-moar 61d231​: OUTPUT«Potential difficulties​:␤ Redeclaration of symbol $_␤ at
  /tmp/7gI9FhwrCH​:1␤ ------> my $b; { my $_⏏ = 5; $b = { .say } }; $_ = 42; $b()␤42␤»

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@p6rt p6rt commented Apr 7, 2016

The RT System itself - Status changed from 'new' to 'open'

@p6rt p6rt added the Bug label Jan 5, 2020
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