sets are unordered, so do not assume that .list preserves order

Raku · Dec 9, 2012 · ad3da93 · ad3da93
1 parent ed49c88
commit ad3da93
Showing 1 changed file with 2 additions and 2 deletions.
diff --git a/S02-types/set.t b/S02-types/set.t
@@ -223,11 +223,11 @@ sub showset($s) { $s.keys.sort.join(' ') }
 
 # RT 107022
 {
-    is_deeply [ ( set ( set <a b c> ), <c> ).list ], [ 'a', 'b', 'c' ],
+    is_deeply [ ( set ( set <a b c> ), <c> ).list.sort ], [ 'a', 'b', 'c' ],
         'set inside set does not duplicate elements';
 
     my $s = set <a b c>;
-    is_deeply [ ( set $s, <c> ).list ], [ 'a', 'b', 'c' ],
+    is_deeply [ ( set $s, <c> ).list.sort ], [ 'a', 'b', 'c' ],
         'variable of Set type inside set does not duplicate elements';
 }