✨ feat: 利用配置的解锁服务获取下载链接#761
Conversation
Summary of ChangesHello @kazukokawagawa, I'm Gemini Code Assist1! I'm currently reviewing this pull request and will post my feedback shortly. In the meantime, here's a summary to help you and other reviewers quickly get up to speed! 此拉取请求引入了一项新功能,允许用户通过配置的解锁服务获取歌曲下载链接。这一功能在用户界面中以一个可切换的设置项呈现,并优先于现有的默认下载方式。它旨在为用户提供更多获取高质量下载资源的途径,并增强了下载逻辑的灵活性和鲁棒性。 Highlights
Using Gemini Code AssistThe full guide for Gemini Code Assist can be found on our documentation page, here are some quick tips. Invoking Gemini You can request assistance from Gemini at any point by creating a comment using either
Customization To customize Gemini Code Assist for GitHub experience, repository maintainers can create a configuration file and/or provide a custom code review style guide (such as PEP-8 for Python) by creating and adding files to a Limitations & Feedback Gemini Code Assist may make mistakes. Please leave feedback on any instances where its feedback is incorrect or counter productive. You can react with 👍 and 👎 on @gemini-code-assist comments. If you're interested in giving your feedback about your experience with Gemini Code Assist for Github and other Google products, sign up here. You can also get AI-powered code generation, chat, as well as code reviews directly in the IDE at no cost with the Gemini Code Assist IDE Extension. Footnotes
|
| const artist = Array.isArray(song.artists) ? song.artists[0].name : song.artists; | ||
| const keyWord = song.name + "-" + artist; |
There was a problem hiding this comment.
获取歌手名的方式存在风险。如果 song.artists 是一个空数组 [],song.artists[0] 会是 undefined,此时访问 .name 属性会抛出 TypeError,导致下载流程中断。
建议使用可选链(?.)和空值合并运算符(??)或逻辑或(||)来安全地获取歌手名,避免潜在的运行时错误。
const artist = (Array.isArray(song.artists) ? song.artists[0]?.name : song.artists) || "";
const keyWord = `${song.name}-${artist}`;这样可以确保 artist 总是一个字符串,即使 song.artists 是空数组或 song.artists[0].name 不存在。
| const artist = Array.isArray(song.artists) ? song.artists[0].name : song.artists; | |
| const keyWord = song.name + "-" + artist; | |
| const artist = (Array.isArray(song.artists) ? song.artists[0]?.name : song.artists) || ""; | |
| const keyWord = `${song.name}-${artist}`; |
| // 尝试推断类型 | ||
| if (url.includes(".flac")) type = "flac"; | ||
| else if (url.includes(".ogg")) type = "ogg"; | ||
| else if (url.includes(".wav")) type = "wav"; | ||
| else if (url.includes(".m4a")) type = "m4a"; | ||
| else type = "mp3"; |
There was a problem hiding this comment.
使用 url.includes(".ext") 来推断文件类型不够健壮。如果 URL 的其他部分(如查询参数)包含了 ".flac" 等字符串,可能会导致错误的类型推断。例如 .../file.mp3?param=.flac。
建议通过解析 URL 的路径名来获取文件扩展名,这样更准确可靠。
// 尝试推断类型
const extensionMatch = url.match(/\.([a-z0-9]+)(?:[?#]|$)/i);
const extension = extensionMatch ? extensionMatch[1].toLowerCase() : null;
switch (extension) {
case "flac":
case "ogg":
case "wav":
case "m4a":
type = extension;
break;
default:
type = "mp3";
}这个正则表达式会从 URL 中提取最后一个 . 之后的文件扩展名,并忽略查询字符串和哈希,从而更准确地判断文件类型。
// 尝试推断类型
const extensionMatch = url.match(/\.([a-z0-9]+)(?:[?#]|$)/i);
const extension = extensionMatch ? extensionMatch[1].toLowerCase() : null;
switch (extension) {
case "flac":
case "ogg":
case "wav":
case "m4a":
type = extension;
break;
default:
type = "mp3";
}

No description provided.