diff --git a/linear-algebra/source/future-ON/01.ptx b/linear-algebra/source/future-ON/01.ptx index cd5c34969..471381289 100644 --- a/linear-algebra/source/future-ON/01.ptx +++ b/linear-algebra/source/future-ON/01.ptx @@ -148,8 +148,32 @@ The dot product combines two vectors and creates a scalar that gives us geometri

Need to create a segue to the fact that you can find the angle between vectors using the Law of Cosines as a starting place.

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Given two vectors \vec u and \vec v in \IR^n, such that \vec u and \vec v are not parallel, let \theta be the angle between the two vectors, + then + + \cos \theta = \frac{\vec u \cdot \vec v }{|\vec u||\vec v|}. + + By the Law of Cosine: + + |\vec u- \vec v|^2 = |\vec u|^2+|\vec v|^2- 2 |\vec u||\vec v| \cos \theta. + + Using dot product of vector \vec u-\vec v with itself: + + + |\vec u- \vec v|^2 \amp = (\vec u- \vec v) \cdot (\vec u- \vec v) \amp + \amp = \vec u \cdot \vec u - 2 ( \vec u \cdot \vec v) + \vec v \cdot \vec v \amp + \amp = |\vec u|^2 - 2 ( \vec u.\vec v) + |\vec v|^2 \amp + +Hence from above, we have: + + \vec u \cdot \vec v = |\vec u||\vec v| \cos \theta . + +

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One of these activity should be deleted from here.

@@ -159,8 +183,22 @@ The dot product combines two vectors and creates a scalar that gives us geometri

Describe all vectors \vec w that are orthogonal to \vec u.

Find the angle between \vec u and \vec v.

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Consider two vectors \vec u =\left[\begin{array}{c} 1 \\ 3 \\ 4 \\ -4 \end{array}\right] and \vec v = \left[\begin{array}{c} -1 \\ -3 \\ -4 \\ 4 \end{array}\right].

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Use dot product to determine |\vec u| and |\vec v|.

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Using dot product, find the distance between \vec u and \vec v .

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Find the angle between \vec u and \vec v.

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