Word frequency

[Yeswanth-Chippada]

def word_count(str):
counts = dict()
words = str.split()

for word in words:
    if word in counts:
        counts[word] += 1
    else:
        counts[word] = 1

return counts

print( word_count('the quick brown fox jumps over the lazy dog.'))

[cclauss]

str is a basic datatype in Python so it is not an appropriate variable name.

https://docs.python.org/3.8/library/collections.html#collections.Counter makes these algorirms trivial in Python.