Can't get fd working with counsel-file-jump

[andreyorst]

Not related to #1926.

I've set my find-program to fd like this:

(setq find-program "fd"))

After that I've set up counsel-file-jump-args:

(setq counsel-file-jump-args (split-string "-L --type f --hidden")))

And when I use counsel-file-jump I get truncated names:

those are .bashrc, .zshrc, and .gitconfig.

I've inspected the code and saw that counsel--find-return-list truncates the line by 2 characters:

swiper/counsel.el

Lines 2611 to 2612 in 20d604c

	(push (buffer-substring
	(+ 2 (line-beginning-position)) (line-end-position)) files)

Assuming that input was ./.bashrc, ./.zshrc, and ./.gitconfig truncating will result to proper file names. However fd omits ./ in the beginning of the path, which leads to my problem.

How should I migrate this?

[andreyorst]

I can get it working with ripgrep but since counsel-file-jump-args is now a list, how do I specify --glob '!.git/ argument for rg?

All of these isn't working:

'("." "--files" "--glob '!.git/'")
'("." "--files" "--glob" "'!.git/'")
'("." "--files" "--glob" "\\'!.git/\\'")
'("." "--files" "--glob" "\"!.git/\"")
'("." "--files" "--glob=\\!.git/")

[abo-abo]

Thanks, please test. The "./" issue should be gone now. If there's still something missing, please open a new issue.

[andreyorst]

Yes, everything works as expected now