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#number of paths to a node follow pascal's triangle
#first diagonal has 1
#second diagonal has 1, 1
#thrird diagonal has 1, 2, 1
#etc
#
#in a 2x2 square, the bottom left is the "center" value of row 4
#for an x by x square, the bottom left will be xth value of row 2x
#choose (2x, x)
#
require 'euler'
sides = 20
puts (2*sides).choose(sides)
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