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[SR-2119] Protocol methods of superclass should be treated as superclass API in subclasses #44727

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an0 mannequin opened this issue Jul 19, 2016 · 0 comments
Closed

[SR-2119] Protocol methods of superclass should be treated as superclass API in subclasses #44727

an0 mannequin opened this issue Jul 19, 2016 · 0 comments

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@an0
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Mannequin

@an0 an0 mannequin commented Jul 19, 2016

Previous ID SR-2119
Radar None
Original Reporter @an0
Type Bug
Status Resolved
Resolution Duplicate
Environment

Swift 3 in Xcode 8.0 beta 3

Additional Detail from JIRA
Votes 0
Component/s Compiler
Labels Bug
Assignee None
Priority Medium

md5: 6ccb97ed31171e7abf704a2cb03475e4

duplicates:

  • SR-103 Protocol Extension: function's implementation cannot be overridden by a subclass

Issue Description:

Compiler reports this error for `Bar.f` overriding `Foo.f`(offered by default implementation in `P` extension):

error: method does not override any method from its superclass

protocol P {
    func f()
}

extension P {
    func f() {}
}

class Foo: P {
//    func f() {}
}

class Bar: Foo {
    // Why no `override`? From what `Bar` sees its superclass `Foo` implements `P`'s interface, whether with explicit implementation of `f` in itself or borrowed implementation of `f` from `P`'s extension. Uncomment Foo.f() to see the contradictory behavior.
    override func f() {}
}
@swift-ci swift-ci transferred this issue from apple/swift-issues Apr 25, 2022
This issue was closed.
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