1897. Redistribute Characters to Make All Strings Equal

1897. Redistribute Characters to Make All Strings Equal (Easy)

You are given an array of strings words (0-indexed).

In one operation, pick two distinct indices i and j, where words[i] is a non-empty string, and move any character from words[i] to any position in words[j].

Return true if you can make every string in words equal using any number of operations, and false otherwise.

 

Example 1:

Input: words = ["abc","aabc","bc"]
Output: true
Explanation: Move the first 'a' in words[1] to the front of words[2],
to make words[1] = "abc" and words[2] = "abc".
All the strings are now equal to "abc", so return true.

Example 2:

Input: words = ["ab","a"]
Output: false
Explanation: It is impossible to make all the strings equal using the operation.

 

Constraints:

• 1 <= words.length <= 100
• 1 <= words[i].length <= 100
• words[i] consists of lowercase English letters.

Companies:
Moengage

Related Topics:
String, Greedy

Solution 1.

// OJ: https://leetcode.com/problems/redistribute-characters-to-make-all-strings-equal/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
    bool makeEqual(vector<string>& A) {
        int cnt[26] = {};
        for (auto &s : A) {
            for (char c : s) cnt[c - 'a']++;
        }
        for (int i = 0; i < 26; ++i) {
            if (cnt[i] % A.size()) return false;
        }
        return true;
    }
};