diff --git a/dbSchema/shopping_cart.dbs b/dbSchema/shopping_cart.dbs new file mode 100644 index 0000000..22c3cb0 --- /dev/null +++ b/dbSchema/shopping_cart.dbs @@ -0,0 +1,89 @@ + + + + + + + + + + + + +
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+ + + + + + + + + \ No newline at end of file diff --git a/employees.sql b/employees.sql new file mode 100644 index 0000000..b09ab0b --- /dev/null +++ b/employees.sql @@ -0,0 +1,108 @@ +-- Sample employee database +-- See changelog table for details +-- Copyright (C) 2007,2008, MySQL AB +-- +-- Original data created by Fusheng Wang and Carlo Zaniolo +-- http://www.cs.aau.dk/TimeCenter/software.htm +-- http://www.cs.aau.dk/TimeCenter/Data/employeeTemporalDataSet.zip +-- +-- Current schema by Giuseppe Maxia +-- Data conversion from XML to relational by Patrick Crews +-- +-- This work is licensed under the +-- Creative Commons Attribution-Share Alike 3.0 Unported License. +-- To view a copy of this license, visit +-- http://creativecommons.org/licenses/by-sa/3.0/ or send a letter to +-- Creative Commons, 171 Second Street, Suite 300, San Francisco, +-- California, 94105, USA. +-- +-- DISCLAIMER +-- To the best of our knowledge, this data is fabricated, and +-- it does not correspond to real people. +-- Any similarity to existing people is purely coincidental. +-- + +DROP DATABASE IF EXISTS employees; +CREATE DATABASE IF NOT EXISTS employees; +USE employees; + +SELECT 'CREATING DATABASE STRUCTURE' as 'INFO'; + +DROP TABLE IF EXISTS dept_emp, + dept_manager, + titles, + salaries, + employees, + departments; + +/*!50503 set default_storage_engine = InnoDB */; +/*!50503 select CONCAT('storage engine: ', @@default_storage_engine) as INFO */; + +CREATE TABLE employees ( + emp_no INT NOT NULL, + birth_date DATE NOT NULL, + first_name VARCHAR(14) NOT NULL, + last_name VARCHAR(16) NOT NULL, + gender ENUM ('M','F') NOT NULL, + hire_date DATE NOT NULL, + PRIMARY KEY (emp_no) +); + +CREATE TABLE departments ( + dept_no CHAR(4) NOT NULL, + dept_name VARCHAR(40) NOT NULL, + PRIMARY KEY (dept_no), + UNIQUE KEY (dept_name) +); + +CREATE TABLE dept_manager ( + emp_no INT NOT NULL, + dept_no CHAR(4) NOT NULL, + from_date DATE NOT NULL, + to_date DATE NOT NULL, + FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE, + FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE, + PRIMARY KEY (emp_no,dept_no) +); + +CREATE TABLE dept_emp ( + emp_no INT NOT NULL, + dept_no CHAR(4) NOT NULL, + from_date DATE NOT NULL, + to_date DATE NOT NULL, + FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE, + FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE, + PRIMARY KEY (emp_no,dept_no) +); + +CREATE TABLE titles ( + emp_no INT NOT NULL, + title VARCHAR(50) NOT NULL, + from_date DATE NOT NULL, + to_date DATE, + FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE, + PRIMARY KEY (emp_no,title, from_date) +) +; + +CREATE TABLE salaries ( + emp_no INT NOT NULL, + salary INT NOT NULL, + from_date DATE NOT NULL, + to_date DATE NOT NULL, + FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE, + PRIMARY KEY (emp_no, from_date) +) +; + +CREATE OR REPLACE VIEW dept_emp_latest_date AS + SELECT emp_no, MAX(from_date) AS from_date, MAX(to_date) AS to_date + FROM dept_emp + GROUP BY emp_no; + +# shows only the current department for each employee +CREATE OR REPLACE VIEW current_dept_emp AS + SELECT l.emp_no, dept_no, l.from_date, l.to_date + FROM dept_emp d + INNER JOIN dept_emp_latest_date l + ON d.emp_no=l.emp_no AND d.from_date=l.from_date AND l.to_date = d.to_date; \ No newline at end of file diff --git a/queries.sql b/queries.sql new file mode 100644 index 0000000..2f00456 --- /dev/null +++ b/queries.sql @@ -0,0 +1,311 @@ + +--INSERT DATA------------------------------------------------------------------------------------------------------------------------------------------ + + --Insert at least 15 new employees: + + INSERT INTO `employees`(`emp_no`, `birth_date`, `first_name`, `last_name`, `gender`, `hire_date`) + VALUES + ('1', '1991-12-12', 'David', 'Lopez', 1,'2021-12-21'), + ('2', '1993-08-07', 'Dias', 'Obraador', 1,'2006-10-22'), + ('3', '1971-09-07', 'Beatriz', 'Martinez', 2,'2000-09-12'), + ('4', '1956-09-12', 'Antonio', 'Cid', 1, '1986-09-09'), + ('5', '1976-07-09', 'Ilda', 'Moralez', 1, '2021-12-11'), + ('6', '1987-03-12', 'Lucia', 'Pizarro', 2, '1996-12-32'), + ('7', '1980-12-01', 'Fernando', 'Martinez', 1, '1999-01-30'), + ('8', '1969-04-02', 'Sergio', 'Izada', 1, '2001-05-12'), + ('9', '1999-04-12', 'Ruben', 'Zafra', 1, '2003-07-12'), + ('10', '1945-02-45', 'Kristian', 'Kasir', 1, '2021-07-21'), + ('11', '1976-05-13', 'Berta', 'Romero', 2, '1995-06-11'), + ('12', '1945-10-28', 'Javier', 'Pascual', 1, '1986-12-22'), + ('13', '1978-12-22', 'Antonio', 'Rufino', 1, '2021-03-11'), + ('14', '1999-05-12', 'Isaura', 'Torres', 2, '2001-08-11'), + ('15', '1995-08-30', 'Kenny', 'Naranjo', 1, '2000-12-12'); + + + --With salaries that are between a range of 5,000 and 50,000 of different gender + -- 5 employees must have at least two salaries in different ranges of dates and different amounts + + INSERT INTO `salaries` (`emp_no`, `salary`, `from_date`, `to_date`) + VALUES + ('1', '5000', '2021-12-21', '2026-12-21'), + ('2', '10000', '2006-10-22', '2016-10-22'), + ('3', '30000', '2000-09-12', '2024-09-12'), + ('4', '15000', '1986-09-09', '1999-09-09'), + ('5', '50000', '2021-12-11', '2030-12-11'), + ('6', '40000', '1999-06-11', '2030-06-11'), + ('7', '45000', '1999-01-30', '2030-01-30'), + ('8', '38000', '2001-05-12', '2050-05-12'), + ('9', '50000', '2003-07-12', '2050-07-12'), + ('10', '30000', '2021-07-21', '2045-07-21'), + ('11', '33000', '1995-06-11', '2040-06-11'), + ('12', '30000', '1986-12-22', '2002-12-22'), + ('13', '27000', '2021-03-11', '2040-03-11'), + ('14', '23000', '2001-08-11', '2050-08-11'), + ('15', '50000', '2000-12-12', '2040-12-12'), + ('15', '16000', '2040-12-12', '2050-12-12'), + ('14', '34000', '2050-08-11', '2060-08-11'), + ('13', '45000', '2040-03-11', '2050-03-11'), + ('12', '36000', '2002-12-22', '2004-12-22'), + ('11', '46000', '2040-06-11', '2050-06-11'); + + + --Creating departaments + + INSERT INTO `departments` (`dept_no`, `dept_name`) + VALUES + ('1', 'human_resources'), + ('2', 'administration'), + ('3', 'facturation'); + + + + --10 employees belong to more than one department + + INSERT INTO `dept_emp` (`emp_no`, `dept_no`, `from_date`, `to_date`) + VALUES + ('1', '2', '2021-12-21', '2024-12-21'), + ('2', '1', '2006-10-22', '2012-10-22'), + ('3', '1', '2000-09-12', '2022-09-12'), + ('4', '3', '1986-09-09', '2000-09-09'), + ('5', '1', '2021-12-11', '2022-12-11'), + ('6', '1', '1999-06-11', '2015-06-11'), + ('7', '2', '1999-01-30', '2020-01-30'), + ('8', '1', '2001-05-12', '2018-05-12'), + ('9', '1', '2003-07-12', '2015-07-12'), + ('10', '1', '2021-07-21', '2045-07-21'), + ('11', '1', '1995-06-11', '2030-06-11'), + ('12', '1', '1986-12-22', '2032-12-22'), + ('13', '3', '2021-03-11', '2027-03-11'), + ('14', '1', '2001-08-11', '2030-08-11'), + ('15', '1', '2000-12-12', '2015-12-12'), + ('1', '1', '2022-12-21', '2030-12-21'), + ('2', '2', '2007-10-22', '2017-10-22'), + ('3', '2', '2003-09-12', '2021-09-12'), + ('4', '1', '1987-09-09', '2014-09-09'), + ('5', '2', '2022-12-11', '2026-12-11'), + ('6', '2', '2012-06-11', '2018-06-11'), + ('7', '1', '2013-01-30', '2019-01-30'), + ('8', '2', '2011-05-12', '2021-05-12'), + ('9', '3', '2003-07-12', '2019-07-12'), + ('10', '3', '2022-07-21', '2030-07-21'); + + -- 5 employees are managers + + INSERT INTO `dept_manager` (`emp_no`, `dept_no`, `from_date`, `to_date`) + VALUES + ('14', '1', '2022-12-11', '2030-12-11'), + ('12', '2', '1987-12-22', '2000-12-22'), + ('15', '3', '2000-12-12', '2019-12-12'), + ('13', '1', '2022-03-11', '2038-03-11'), + ('11', '2', '2022-12-11', '2037-12-11'); + + + -- All employees have a degree and at least 5 titles are from 2020 + + INSERT INTO `titles` (`emp_no`, `title`, `from_date`, `to_date`) VALUES + ('1', 'Data science', '2020-06-05', NULL), + ('2', 'Data science', '2020-07-07', NULL), + ('3', 'Data science', '2020-07-07', NULL), + ('4', 'Data science', '2020-03-07', NULL), + ('5', 'Machine learning', '2020-03-07', NULL), + ('6', 'Machine learning', '2020-08-07', NULL), + ('7', 'Machine learning', '1985-03-12', NULL), + ('8', 'Machine learning', '1996-08-24', NULL), + ('9', 'Machine learning', '2001-10-02', NULL), + ('10', 'Data science', '2004-11-03', NULL), + ('11', 'Business Management', '2007-02-02', NULL), + ('12', 'Business Management', '2016-07-05', NULL), + ('13', 'Business Management', '2019-01-15', NULL), + ('14', 'Business Management', '2002-04-08', NULL), + ('15', 'Business Management', '1985-03-05', NULL); + + + -- At least 3 employees have the same name + + --(I had already created 2 employees with the same name so I have updated one so that there are a total of 3) + + UPDATE `employees` SET `first_name` = 'Antonio' WHERE `employees`.`emp_no` = 1; + + + + + + +-- UPDATE DATA------------------------------------------------------------------------------------------------------------------------------------------ + + --Change the name of an employee. To do this, generate a query that affects only a certain employee based on their name, surname and date of birth. + + UPDATE employees + SET first_name='Pedro' + WHERE first_name='Paco' ,last_name='Gonzalez', birth_date='1993-06-02'; + + + -- Change the name of all departments. + + UPDATE departments SET dept_name ='administration-dept' WHERE dept_no = 2; + UPDATE departments SET dept_name ='facturation-dept' WHERE dept_no = 1; + UPDATE departments SET dept_name ='human-resources-dept' WHERE dept_no = 3; + + + + + + +-- GET DATA------------------------------------------------------------------------------------------------------------------------------------------ + + -- Select all employees with a salary greater than 20,000, you must list all employees data and the salary. + + SELECT * + FROM employees + INNER JOIN salaries + ON employees.emp_no = salaries.emp_no + WHERE salary > 20000; + + + + -- Select all employees with a salary below 10,000, you must list all employees data and the salary. + + SELECT * + FROM employees + INNER JOIN salaries + ON employees.emp_no = salaries.emp_no + WHERE salary < 10000; + + + + -- Select all employees who have a salary between 14,000 and 50,000, you must list all employees data and the salary. + + SELECT * + FROM employees + INNER JOIN salaries + ON employees.emp_no = salaries.emp_no + WHERE salary BETWEEN 14000 AND 50000; + + + + -- Select the total number of employees + + SELECT COUNT(*) as total_employees FROM employees; + + + + -- Select the total number of employees who have worked in more than one department + + SELECT emp_no, COUNT(*) AS Number_of_departments_worked FROM dept_emp GROUP BY emp_no HAVING COUNT(*) > 1; + + + + -- Select the titles of the year 2020 + + SELECT * FROM `titles` WHERE from_date > '2019-12-31'; + + + + --Select the name of all employees with capital letters + + SELECT UPPER(first_name) FROM `employees`; + + + + -- Select the name, surname and name of the current department of each employee + + SELECT first_name, last_name, departments.dept_name + FROM employees + INNER JOIN dept_emp ON employees.emp_no = dept_emp.emp_no + INNER JOIN departments ON dept_emp.dept_no = departments.dept_no; + + + + -- Select the name, surname and number of times the employee has worked as a manager + + SELECT first_name, last_name, dept_manager.from_date, dept_manager.to_date + FROM employees + INNER JOIN dept_manager ON employees.emp_no = dept_manager.emp_no; + + + + -- Select the name of employees without any being repeated + + SELECT DISTINCT first_name FROM employees; + + + + + + +-- DELETE DATA------------------------------------------------------------------------------------------------------------------------------------------ + + -- Delete all employees with a salary greater than 20,000 + + DELETE FROM salaries WHERE salary > 20000; + + + + --Remove the department that has more employees. (Let’s assume that only one department is returned in this query, as an extra you can try to write the query for deleting all departments in case there are more than one in the result) + + -- View num of employees for department + + SELECT dept_no, COUNT(*) AS employees_for_departments FROM dept_emp GROUP BY dept_no HAVING COUNT(*) > 1; + + -- Since we already know which department has the most employees, we delete it + + DELETE FROM departments WHERE dept_no = 1; + + + + +-- DESIGN YOUR OWN DATABASE + + -- Create and use database + + CREATE DATABASE `shopping_cart` USE shopping_cart; + + + -- Create tables + CREATE TABLE `shopping_cart`.customers + (first_name VARCHAR(20) NOT NULL , + PRIMARY KEY (customer_id), + last_name VARCHAR(20) NOT NULL , + birth_day DATE NOT NULL , + email VARCHAR(40) NOT NULL , + gender ENUM('M','F') NOT NULL , + customer_id INT NOT NULL AUTO_INCREMENT); + + + CREATE TABLE shopping_cart.orders + (quantity INT NOT NULL , + PRIMARY KEY (no_order), + no_order INT NOT NULL AUTO_INCREMENT, + customer_id INT NOT NULL, + FOREIGN KEY (customer_id) REFERENCES customers(customer_id); + ON DELETE CASCADE, id_article INT NOT NULL, + FOREIGN KEY (id_article) + REFERENCES article(id_article) + ON DELETE CASCADE); + + + CREATE TABLE shopping_cart.article + (article_name VARCHAR(50) NOT NULL , + PRIMARY KEY (id_article), + id_article INT NOT NULL AUTO_INCREMENT); + + + CREATE TABLE shopping_cart.pay_methods + (paypal VARCHAR(40) NOT NULL , + cards INT(50) NOT NULL , + id_pay_methods INT NOT NULL AUTO_INCREMENT, + PRIMARY KEY (id_pay_methods), + FOREIGN KEY (no_order) REFERENCES orders(no_order) ON DELETE CASCADE, + no_order INT NOT NULL, + FOREIGN KEY (customer_id) REFERENCES customers(customer_id) ON DELETE CASCADE, + customer_id INT NOT NULL); + + + CREATE TABLE shopping_cart.invoices + (PRIMARY KEY (invoice_no), invoice_no INT NOT NULL AUTO_INCREMENT, + FOREIGN KEY (customer_id) REFERENCES customers(customer_id) + ON DELETE CASCADE, customer_id INT NOT NULL, + FOREIGN KEY (id_pay_methods) + REFERENCES pay_methods(id_pay_methods) + ON DELETE CASCADE, + id_pay_methods INT NOT NULL); \ No newline at end of file