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Solution: Iuliia Shikhanova #36

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111 changes: 111 additions & 0 deletions employees.sql
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-- Sample employee database
-- See changelog table for details
-- Copyright (C) 2007,2008, MySQL AB
--
-- Original data created by Fusheng Wang and Carlo Zaniolo
-- http://www.cs.aau.dk/TimeCenter/software.htm
-- http://www.cs.aau.dk/TimeCenter/Data/employeeTemporalDataSet.zip
--
-- Current schema by Giuseppe Maxia
-- Data conversion from XML to relational by Patrick Crews
--
-- This work is licensed under the
-- Creative Commons Attribution-Share Alike 3.0 Unported License.
-- To view a copy of this license, visit
-- http://creativecommons.org/licenses/by-sa/3.0/ or send a letter to
-- Creative Commons, 171 Second Street, Suite 300, San Francisco,
-- California, 94105, USA.
--
-- DISCLAIMER
-- To the best of our knowledge, this data is fabricated, and
-- it does not correspond to real people.
-- Any similarity to existing people is purely coincidental.
--

DROP DATABASE IF EXISTS employees;
CREATE DATABASE IF NOT EXISTS employees;
USE employees;

SELECT 'CREATING DATABASE STRUCTURE' as 'INFO';

DROP TABLE IF EXISTS dept_emp,
dept_manager,
titles,
salaries,
employees,
departments;

/*!50503 set default_storage_engine = InnoDB */;
/*!50503 select CONCAT('storage engine: ', @@default_storage_engine) as INFO */;

CREATE TABLE employees (
emp_no INT NOT NULL,
birth_date DATE NOT NULL,
first_name VARCHAR(14) NOT NULL,
last_name VARCHAR(16) NOT NULL,
gender ENUM ('M','F') NOT NULL,
hire_date DATE NOT NULL,
PRIMARY KEY (emp_no)
);

CREATE TABLE departments (
dept_no CHAR(4) NOT NULL,
dept_name VARCHAR(40) NOT NULL,
PRIMARY KEY (dept_no),
UNIQUE KEY (dept_name)
);

CREATE TABLE dept_manager (
emp_no INT NOT NULL,
dept_no CHAR(4) NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,dept_no)
);

CREATE TABLE dept_emp (
emp_no INT NOT NULL,
dept_no CHAR(4) NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,dept_no)
);

CREATE TABLE titles (
emp_no INT NOT NULL,
title VARCHAR(50) NOT NULL,
from_date DATE NOT NULL,
to_date DATE,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,title, from_date)
)
;

CREATE TABLE salaries (
emp_no INT NOT NULL,
salary INT NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no, from_date)
)
;

CREATE OR REPLACE VIEW dept_emp_latest_date AS
SELECT emp_no, MAX(from_date) AS from_date, MAX(to_date) AS to_date
FROM dept_emp
GROUP BY emp_no;

# shows only the current department for each employee
CREATE OR REPLACE VIEW current_dept_emp AS
SELECT l.emp_no, dept_no, l.from_date, l.to_date
FROM dept_emp d
INNER JOIN dept_emp_latest_date l
ON d.emp_no=l.emp_no AND d.from_date=l.from_date AND l.to_date = d.to_date;


-- 08:11:51 CREATE TABLE departments ( dept_no CHAR(4) NOT NULL AUTO_INCREMENT, dept_name VARCHAR(40) NOT NULL, PRIMARY KEY (dept_no), UNIQUE KEY (dept_name) ) Error Code: 1063. Incorrect column specifier for column 'dept_no' 0.00030 sec
98 changes: 98 additions & 0 deletions new-database.sql
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-- customer -> contact info / One-To-One
-- customer -> order / one-to-many
-- order -> items / many-to-many


DROP DATABASE IF EXISTS online_shop;
CREATE DATABASE IF NOT EXISTS online_shop;
USE online_shop;

SELECT 'CREATING DATABASE STRUCTURE' as 'INFO';

DROP TABLE IF EXISTS user,
contact_info,
order_regist,
order_details,
items;

/*!50503 set default_storage_engine = InnoDB */;
/*!50503 select CONCAT('storage engine: ', @@default_storage_engine) as INFO */;


CREATE TABLE user (
user_id INT NOT NULL AUTO_INCREMENT NOT NULL,
first_name VARCHAR(50) NULL DEFAULT NULL,
last_name VARCHAR(50) NULL DEFAULT NULL,

PRIMARY KEY (user_id)
);

CREATE TABLE contact_info (
contact_id INT NOT NULL AUTO_INCREMENT,
user_id INT NULL DEFAULT NULL,
country VARCHAR(50) NULL DEFAULT NULL,
city VARCHAR(50) NULL DEFAULT NULL,
adress VARCHAR(50) NULL DEFAULT NULL,
phone_number VARCHAR(15) NULL,
email VARCHAR(50) NULL,

PRIMARY KEY (contact_id),
FOREIGN KEY (user_id)
REFERENCES online_shop.user (user_id),
UNIQUE INDEX `uq_phone_number` (`phone_number` ASC),
UNIQUE INDEX `uq_email` (`email` ASC)
);


CREATE TABLE order_regist (
order_id INT NOT NULL AUTO_INCREMENT,
user_id INT NULL DEFAULT NULL,
item_id INT NULL DEFAULT NULL,
status_ SMALLINT(6) NOT NULL DEFAULT 0,

PRIMARY KEY (order_id),
FOREIGN KEY (user_id)
REFERENCES user (user_id)
);


CREATE TABLE order_details (
od_id INT NOT NULL,
user_id INT NULL DEFAULT NULL,
order_id INT NULL DEFAULT NULL,
item_id INT NULL DEFAULT NULL,
price FLOAT NOT NULL DEFAULT 0,
discount FLOAT NOT NULL DEFAULT 0,
quantity SMALLINT(6) NOT NULL DEFAULT 0,
delivery FLOAT NOT NULL DEFAULT 0,
date_created DATETIME NOT NULL,


PRIMARY KEY (od_id),
FOREIGN KEY (user_id)
REFERENCES user (user_id)
);


CREATE TABLE items (
item_id INT NOT NULL AUTO_INCREMENT,
name_product VARCHAR(75) NOT NULL,
supplier VARCHAR(100) NOT NULL,
price FLOAT NOT NULL DEFAULT 0,
quantity SMALLINT(6) NOT NULL DEFAULT 0,
published DATETIME NULL DEFAULT NULL,
order_id INT NULL DEFAULT NULL,

PRIMARY KEY (item_id),
FOREIGN KEY (order_id)
REFERENCES online_shop.order_regist (order_id)
);









176 changes: 176 additions & 0 deletions query.sql
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-- $$$ Insert data $$$ --

INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (1, '1990-02-09', 'Maria', 'Ivanova', 'F', '2020-02-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (2, '1976-09-30', 'Gomer', 'Simpson', 'M', '2021-06-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (3, '1988-11-12', 'Alfred', 'Morgan', 'M', '2010-04-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (4, '1991-05-21', 'Coco', 'Chanel', 'F', '2018-07-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (5, '1989-10-07', 'Britney', 'Spears', 'F', '2020-04-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (6, '1990-09-03', 'Daniel', 'Green', 'M', '2015-08-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (7, '1992-11-07', 'Elvis', 'Presley', 'M', '2019-09-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (8, '1996-09-23', 'Devid', 'Smith', 'M', '2021-03-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (9, '1987-02-16', 'Maria', 'Duma', 'F', '2018-02-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (10, '1978-05-26', 'Emily', 'Cooper', 'F', '2017-07-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (11, '1993-04-12', 'Li', 'Won', 'M', '2023-01-10');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (12, '1987-07-27', 'Karry', 'Bradshow', 'F', '2010-02-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (13, '1970-07-11', 'Olivia', 'Gonzalez', 'F', '2011-04-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (14, '1974-04-19', 'Maria', 'Dubrova', 'F', '2013-02-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES (15, '1999-12-09', 'Nikita', 'Mikhalkov', 'M', '2013-05-01');

INSERT INTO departments (dept_no, dept_name)
VALUES
('n1', 'Sales'),
('n2', 'Administration'),
('n3', 'HR'),
('n4', 'Finance'),
('n5', 'Customer Service');

INSERT INTO titles (emp_no, title, from_date, to_date)
VALUES
(1, 'Degree in Law', '2020-09-01', now()),
(2, 'Degree in Media and Communication', '2015-09-01', '2019-06-01'),
(3, 'Degree in Social Sciences', '2013-09-01', '2017-06-01'),
(4, 'Degree in Arts and Humanities', '2020-09-01', now()),
(5, 'Master in Business and Economics', '2014-09-01', '2018-06-01'),
(6, 'Master in Media and Communication', '2015-09-01', '2019-06-01'),
(7, 'Master in Law', '2010-09-01', '2014-06-01'),
(8, 'Master in Social Sciences', '2018-09-01', '2022-06-01'),
(9, 'Master in Business and Economics', '2020-09-01', now()),
(10, 'BA in Media and Communication', '2011-09-01', '2015-06-01'),
(11, 'BA in Social Sciences', '2018-09-01', '2022-06-01'),
(12, 'BA in Arts and Humanities', '2020-09-01', now()),
(13, 'BA in Arts and Humanities', '2018-09-01', '2022-06-01'),
(14, 'BA in Law', '2018-09-01', '2022-06-01'),
(15, 'BA in Business and Economics', '2020-09-01', now());

INSERT INTO salaries (emp_no, salary, from_date, to_date)
VALUES
(1, 24000, '2020-02-01', '2021-02-01'),
(1, 30000, '2021-02-02', now()),
(2, 24000, '2021-06-01', '2022-02-01'),
(2, 28000, '2022-02-02', now()),
(3, 18000, '2010-04-01', '2015-09-01'),
(3, 30000, '2015-09-02', now()),
(4, 26000, '2018-07-01', '2019-08-01'),
(4, 32000, '2019-08-02', now()),
(5, 26000, '2020-04-01', '2021-06-01'),
(5, 36000, '2021-06-01', now()),
(6, 31000, '2015-08-01', now()),
(7, 33000, '2019-09-01', now()),
(8, 23000, '2021-03-01', now()),
(9, 28000, '2018-02-01', now()),
(10, 35000, '2017-07-01', now()),
(11, 19000, '2023-01-10', now()),
(12, 45000, '2010-02-01', now()),
(13, 36000, '2011-04-01', now()),
(14, 32000, '2013-02-01', now()),
(15, 39000, '2013-05-01', now());

INSERT INTO dept_manager (emp_no, dept_no, from_date, to_date)
VALUES
(2, 'n1', '2021-06-01', now()),
(13, 'n2', '2011-04-01', '2020-04-02'),
(5, 'n2', '2020-04-02', now()),
(14, 'n3', '2013-02-01', now()),
(2, 'n4', '2021-06-01', '2019-08-31'),
(7, 'n4', '2019-09-01', now()),
(4, 'n5', '2018-07-01', now());

INSERT INTO dept_emp (emp_no, dept_no, from_date, to_date)
VALUES
(1, 'n1', '2020-02-01', '2021-01-31'),
(1, 'n2', '2021-02-01', now()),
(2, 'n2', '2021-06-01', now()),
(3, 'n2', '2010-04-01', '2012-04-01'),
(3, 'n4', '2012-04-02', now()),
(4, 'n3', '2018-07-01', '2020-04-01'),
(4, 'n5', '2020-04-02', now()),
(5, 'n5', '2020-04-01', '2022-06-01'),
(5, 'n3', '2022-06-02', now()),
(6, 'n3', '2015-08-01', now()),
(7, 'n4', '2019-09-01', '2021-06-01'),
(7, 'n1', '2021-06-02', now()),
(8, 'n3', '2021-03-01', '2023-01-01'),
(8, 'n2', '2023-01-02', now()),
(9, 'n4', '2018-02-01', '2020-01-01'),
(9, 'n1', '2020-01-02', now()),
(10, 'n1', '2017-07-01', '2020-05-01'),
(10, 'n5', '2020-05-02', now()),
(11, 'n3', '2023-01-10', now()),
(12, 'n5', '2010-02-01', '2015-09-01'),
(12, 'n1', '2015-09-01', '2020-11-01'),
(12, 'n3', '2020-11-02', now()),
(13, 'n4', '2011-04-01', '2018-11-01'),
(13, 'n2', '2020-11-02', now()),
(14, 'n4', '2013-02-01', '2018-08-01'),
(14, 'n2', '2018-08-02', now()),
(15, 'n3', '2013-05-01', '2018-10-01'),
(15, 'n1', '2018-10-02', now());



-- $$$ UPDATE DATA $$$


SELECT * FROM employees;

-- Change the name of an employee --
UPDATE employees SET first_name = 'Megan' WHERE (first_name = 'Alicia' AND last_name LIKE '%nov%' AND birth_date > '1989-02-01');


SELECT * FROM departments;
-- Change the name of all departments --
UPDATE departments SET dept_name = 'Sales and marketing' WHERE (dept_no = 'n1');
UPDATE departments SET dept_name = 'Finance and Administration' WHERE (dept_no = 'n2');
UPDATE departments SET dept_name = 'PR and Publishing' WHERE (dept_no = 'n3');
UPDATE departments SET dept_name = 'HR and production' WHERE (dept_no = 'n4');
UPDATE departments SET dept_name = 'Customer Service and operations' WHERE (dept_no = 'n5');



-- $$$ GET DATA $$$

-- select ALL from Table "employees" --> add table 'salaries' where match up "emp_no" and salary of tab."salaries" >20000

-- Select all employees with a salary greater than 20,000, you must list all employees data and the salary (+28000 in my case)--
SELECT * FROM employees INNER JOIN salaries ON employees.emp_no = salaries.emp_no AND salaries.salary > 20000;
SELECT * FROM employees INNER JOIN salaries ON employees.emp_no = salaries.emp_no AND salaries.salary > 28000;

-- Select all employees with a salary below 10,000, you must list all employees data and the salary --
SELECT * FROM employees INNER JOIN salaries ON employees.emp_no = salaries.emp_no AND salaries.salary < 20000;

-- Select all employees who have a salary between 14,000 and 50,000, you must list all employees data and the salary --
SELECT * FROM employees INNER JOIN salaries ON employees.emp_no = salaries.emp_no AND salaries.salary BETWEEN 20000 AND 30000;

-- Select the total number of employees --
SELECT COUNT(emp_no) AS 'Number of employees' FROM employees;

-- Select the total number of employees who have worked in more than one department --
SELECT COUNT(emp_no) AS 'Have worked in more than 1 dept' FROM (SELECT emp_no FROM dept_emp GROUP BY emp_no HAVING COUNT(emp_no) > 1) employees;

-- Select the titles of the year 2020 --
SELECT * FROM titles WHERE from_date BETWEEN '2020-01-01' AND '2020-12-31';

-- Select the name of all employees with capital letters --
SELECT UCASE(first_name) FROM employees;

-- Select the name of employees without any being repeated --
SELECT DISTINCT first_name FROM employees;
SELECT COUNT(DISTINCT first_name) FROM employees;

-- Select the name, surname and name of the current department of each employee
SELECT e.first_name, e.last_name, ds.dept_name FROM employees e JOIN dept_emp d ON E.emp_no = d.emp_no JOIN departments ds ON d.dept_no = ds.dept_no;
-- take name+surname from table empl-s and name of dep-t from table departments -> join from table dept_emp (d meams short name of the table) whero matchs id of every employeer and then join -> table dp-ts where match id of dp-table

-- Select the name, surname and number of times the employee has worked as a manager
SELECT e.first_name, e.last_name, COUNT(*) FROM employees e, dept_manager dm WHERE e.emp_no = dm.emp_no GROUP BY e.first_name, e.last_name;



-- $$$ DELETE DATA $$$

-- Delete all employees with a salary greater than 20,000 (35000 in my case)
DELETE employees, salaries FROM employees INNER JOIN salaries ON salaries.emp_no = employees.emp_no AND salaries.salary > 35000;

-- Remove the department that has the most employees
DELETE FROM departments WHERE dept_no = (SELECT dept_no FROM dept_emp GROUP BY dept_no ORDER BY count(dept_no) desc limit 1);