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Solution : Javier Pascual Tunez #49

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108 changes: 108 additions & 0 deletions employees.sql
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-- Sample employee database
-- See changelog table for details
-- Copyright (C) 2007,2008, MySQL AB
--
-- Original data created by Fusheng Wang and Carlo Zaniolo
-- http://www.cs.aau.dk/TimeCenter/software.htm
-- http://www.cs.aau.dk/TimeCenter/Data/employeeTemporalDataSet.zip
--
-- Current schema by Giuseppe Maxia
-- Data conversion from XML to relational by Patrick Crews
--
-- This work is licensed under the
-- Creative Commons Attribution-Share Alike 3.0 Unported License.
-- To view a copy of this license, visit
-- http://creativecommons.org/licenses/by-sa/3.0/ or send a letter to
-- Creative Commons, 171 Second Street, Suite 300, San Francisco,
-- California, 94105, USA.
--
-- DISCLAIMER
-- To the best of our knowledge, this data is fabricated, and
-- it does not correspond to real people.
-- Any similarity to existing people is purely coincidental.
--

DROP DATABASE IF EXISTS employees;
CREATE DATABASE IF NOT EXISTS employees;
USE employees;

SELECT 'CREATING DATABASE STRUCTURE' as 'INFO';

DROP TABLE IF EXISTS dept_emp,
dept_manager,
titles,
salaries,
employees,
departments;

/*!50503 set default_storage_engine = InnoDB */;
/*!50503 select CONCAT('storage engine: ', @@default_storage_engine) as INFO */;

CREATE TABLE employees (
emp_no INT NOT NULL,
birth_date DATE NOT NULL,
first_name VARCHAR(14) NOT NULL,
last_name VARCHAR(16) NOT NULL,
gender ENUM ('M','F') NOT NULL,
hire_date DATE NOT NULL,
PRIMARY KEY (emp_no)
);

CREATE TABLE departments (
dept_no CHAR(4) NOT NULL,
dept_name VARCHAR(40) NOT NULL,
PRIMARY KEY (dept_no),
UNIQUE KEY (dept_name)
);

CREATE TABLE dept_manager (
emp_no INT NOT NULL,
dept_no CHAR(4) NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,dept_no)
);

CREATE TABLE dept_emp (
emp_no INT NOT NULL,
dept_no CHAR(4) NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
FOREIGN KEY (dept_no) REFERENCES departments (dept_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,dept_no)
);

CREATE TABLE titles (
emp_no INT NOT NULL,
title VARCHAR(50) NOT NULL,
from_date DATE NOT NULL,
to_date DATE,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no,title, from_date)
)
;

CREATE TABLE salaries (
emp_no INT NOT NULL,
salary INT NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no, from_date)
)
;

CREATE OR REPLACE VIEW dept_emp_latest_date AS
SELECT emp_no, MAX(from_date) AS from_date, MAX(to_date) AS to_date
FROM dept_emp
GROUP BY emp_no;

# shows only the current department for each employee
CREATE OR REPLACE VIEW current_dept_emp AS
SELECT l.emp_no, dept_no, l.from_date, l.to_date
FROM dept_emp d
INNER JOIN dept_emp_latest_date l
ON d.emp_no=l.emp_no AND d.from_date=l.from_date AND l.to_date = d.to_date;
168 changes: 168 additions & 0 deletions queries.sql
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INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('1', '1980-12-12', 'Jonas', 'Torres', 'M', '2015-04-20');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('2', '1981-12-12', 'Marc', 'Rodriguez', 'M', '2020-02-12');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('3', '1982-12-12', 'Andreu', 'Tunez', 'M', '2010-12-09');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('4', '1983-12-12', 'Monica', 'Llobet', 'F', '2016-06-16');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('5', '1981-12-12', 'Maria', 'Marquez', 'F', '2012-04-12');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('6', '1985-12-12', 'Jesus', 'Garcia', 'M', '2014-02-14');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('7', '1982-12-12', 'Queralt', 'Martinez', 'F', '2018-07-28');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('8', '1983-12-12', 'Sergi', 'Lopez', 'M', '2021-10-24');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('9', '1980-12-12', 'Claudia', 'Sanchez', 'F', '2016-11-14');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('10', '1987-12-12', 'Pilar', 'Perez', 'F', '2015-05-01');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('11', '1986-12-12', 'Antonio', 'Ruiz', 'M', '2011-03-16');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('12', '1989-12-12', 'Daniel', 'Moreno', 'M', '2009-04-12');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('13', '1980-12-12', 'Javier', 'Navarro', 'M', '2022-11-04');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('14', '1981-12-12', 'Javier', 'Alvarez', 'M', '2020-09-10');
INSERT INTO employees (emp_no, birth_date, first_name, last_name, gender, hire_date) VALUES ('15', '1983-12-12', 'Javier', 'Pascual', 'M', '2021-06-17');

-- Con el Insert introduccimos todos los datos de los empleados en nuestra tabla.

INSERT INTO `salaries` (`emp_no`, `salary`, `from_date`, `to_date`) VALUES ('1', '35000', '2015-04-20', '2023-01-20'),
('1', '40000', '2023-01-21', '2024-01-21'),
('2', '30000', '2020-02-12', '2023-01-20'),
('2', '35000', '2023-01-21', '2024-01-21'),
('3', '34000', '2010-12-09', '2023-01-20'),
('3', '39000', '2023-01-21', '2024-01-21'),
('4', '31000', '2016-06-16', '2023-01-20'),
('4', '37000', '2023-01-21', '2024-01-21'),
('5', '35000', '2012-04-12', '2023-01-20'),
('5', '41000', '2023-01-21', '2024-01-21'),
('6', '41500', '2014-02-14', '2023-01-20'),
('7', '40500', '2018-07-28', '2023-01-20'),
('8', '38000', '2021-10-24', '2023-01-20'),
('9', '36000', '2016-11-14', '2023-01-20'),
('10', '45000', '2015-05-01', '2023-01-20'),
('11', '50000', '2011-03-16', '2023-01-20'),
('12', '47000', '2009-04-12', '2023-01-20'),
('13', '44000', '2022-11-04', '2023-01-20'),
('14', '47000', '2020-09-10', '2023-01-20'),
('15', '43000', '2021-06-17', '2023-01-20');

-- Con este Insert into añadimos a la tabla de salarios los salarios de cada empleados durante las fechas señaladas.

INSERT INTO `departments` (`dept_no`, `dept_name`) VALUES
('1', 'Administracion'), ('2', 'Jefatura'), ('3', 'Recepción');

-- Con este Insert into introducimos los diferentes departamentos.

INSERT INTO `dept_emp` (`emp_no`, `dept_no`, `from_date`, `to_date`) VALUES

('1', '1', '2015-04-20', '2023-01-20'), ('1', '2', '2015-04-20', '2023-01-20');
('2', '1', '2020-02-12', '2023-01-20'), ('2', '2', '2020-02-12', '2023-01-20'),
('3', '1', '2010-12-09', '2023-01-20'), ('3', '2', '2010-12-09', '2023-01-20'),
('4', '1', '2016-06-16', '2023-01-20'), ('4', '2', '2016-06-16', '2023-01-20'),
('5', '1', '2012-04-12', '2023-01-20'), ('5', '2', '2012-04-12', '2023-01-20'),
('6', '1', '2014-02-14', '2023-01-20'), ('6', '2', '2014-02-14', '2023-01-20')
('7', '1', '2018-07-28', '2023-01-20'), ('7', '2', '2018-07-28', '2023-01-20'),
('8', '1', '2021-10-24', '2023-01-20'), ('8', '2', '2021-10-24', '2023-01-20'),
('9', '1', '2016-11-14', '2023-01-20'), ('9', '2', '2016-11-14', '2023-01-20'),
('10', '1', '2015-05-01', '2023-01-20'), ('10', '2', '2015-05-01', '2023-01-20'),
('11', '3', '2011-03-16', '2023-01-20'),
('12', '3', '2009-04-12', '2023-01-20'),
('13', '3', '2022-11-04', '2023-01-20'),
('14', '3', '2020-09-10', '2023-01-20'),
('15', '3', '2021-06-17', '2023-01-20');

-- Con este insert into añadimos los diferentes departamentos a cada empleado.

INSERT INTO `dept_manager` (`emp_no`, `dept_no`, `from_date`, `to_date`) VALUES

('1', '1', '2022-06-20', '2023-01-20'),
('2', '1', '2022-06-20', '2023-01-20'),
('3', '2', '2022-01-24', '2023-01-20'),
('4', '2', '2022-01-24', '2023-01-20'),
('5', '1', '2022-06-20', '2023-01-20');

-- Con este insert into añadimos a los empleados los cargos a los que pertenecen en su departamento.

INSERT INTO `titles` (`emp_no`, `title`, `from_date`, `to_date`) VALUES

('1', 'Grado en Ingeniería del Software', '2015-04-20', '2023-01-20'), ('1', 'Master en Assembler Institute of Technology', '2020-06-20', '2023-01-20'),
('2', 'Grado en Ingeniería del Software', '2020-02-12', '2023-01-20'), ('2', 'Master en Assembler Institute of Technology', '2020-06-20', '2023-01-20'),
('3', 'Grado en Ingeniería del Software', '2010-12-09', '2023-01-20'), ('3', 'Master en Assembler Institute of Technology', '2020-06-20', '2023-01-20'),
('4', 'Grado en Ingeniería del Software', '2016-06-16', '2023-01-20'), ('4', 'Master en Assembler Institute of Technology', '2020-06-20', '2023-01-20'),
('5', 'Grado en Ingeniería del Software', '2012-04-12', '2023-01-20'), ('5', 'Master en Assembler Institute of Technology', '2020-06-20', '2023-01-20'),
('6', 'Grado en Ingeniería del Software', '2014-02-14', '2023-01-20'),
('7', 'Grado en Ingeniería del Software', '2018-07-28', '2023-01-20'),
('8', 'Grado en Ingeniería del Software', '2021-10-24', '2023-01-20'),
('9', 'Grado en Ingeniería del Software', '2016-11-14', '2023-01-20'),
('10', 'Grado en Ingeniería del Software', '2015-05-01', '2023-01-20'),
('11', 'Grado en Ingeniería del Software', '2011-03-16', '2023-01-20'),
('12', 'Grado en Ingeniería del Software', '2009-04-12', '2023-01-20'),
('13', 'Grado en Ingeniería del Software', '2022-11-04', '2023-01-20'),
('14', 'Grado en Ingeniería del Software', '2020-09-10', '2023-01-20'),
('15', 'Grado en Ingeniería del Software', '2021-06-17', '2023-01-20');

-- Por ultimo hacemos Insert into para determinar la titulacion de cada empleado.

UPDATE employees SET first_name = 'Marcos', last_name = 'Buenafuente', birth_date = '1980-12-13' WHERE emp_no = 1;

-- Cambiamos el nomrbre, apellido y fecha de nacimiento del empleado.

UPDATE departments Set dept_name = 'Limpieza' WHERE dept_no = 1;
UPDATE departments Set dept_name = 'Caja' WHERE dept_no = 2;
UPDATE departments Set dept_name = 'Revisor' WHERE dept_no = 3;

-- Cambiamos los departamentos de trabajo.

SELECT salary > 20000, from_date FROM salaries;

-- Empleados por encima de los 20.000

SELECT salary < 10000, from_date FROM salaries;

-- Empleados pro debajo de los 10.000

SELECT salary, from_date FROM salaries WHERE salary >= 14000 AND salary <= 50000;

-- Empleados entre los 14.000 y los 50.000

SELECT emp_no FROM employees;

-- Seleccion de todos los trabajadores

SELECT emp_no, dept_no FROM dept_emp WHERE dept_no = 1 AND 2;

-- Empleados que trabajan en 2 departamentos

SELECT from_date FROM titles WHERE from_date LIKE '2020%';

-- Empleados con titulos a partir de 2020

SELECT * FROM employees WHERE first_name NOT LIKE '%[abcdefghijklmnopqrstuvwxyz]%';

-- Empleados que contengan una letra mayuscula

SELECT employees.first_name, employees.last_name, dept_emp.dept_no FROM employees LEFT JOIN dept_emp ON employees.emp_no = dept_emp.emp_no;

-- Seleccionamos el nombre y apellido de cada trabajador y su respectivo departamento.

SELECT employees.first_name, employees.last_name, dept_manager.dept_no FROM employees LEFT JOIN dept_manager ON employees.emp_no = dept_manager.emp_no;

-- Seleccion de nombre y apellido

SELECT DISTINCT first_name FROM employees;

-- Seleccion de empleados con nombres que no se repiten

DELETE FROM salaries WHERE salary <= 20000;

-- Eliminamos los salarios inferior a 20.000

DELETE FROM dept_emp Where MAX(dept_no);


CREATE TABLE `sqlbasics`.`institute` (`Inst_name` VARCHAR(50) NOT NULL , `Inst_adress` VARCHAR(50) NOT NULL , `ID_inst` INT(10) NOT NULL AUTO_INCREMENT , PRIMARY KEY (`ID_inst`)) ENGINE = InnoDB;

CREATE TABLE `sqlbasics`.`teachers` (`ID_teacher` INT(10) NOT NULL AUTO_INCREMENT , `first_name_teacher` VARCHAR(50) NOT NULL , `last_name_teacher` VARCHAR(50) NOT NULL , `class_teacher` VARCHAR(50) NOT NULL , PRIMARY KEY (`last_name_teacher`, `ID_teacher`)) ENGINE = InnoDB;

CREATE TABLE `sqlbasics`.`student` (`ID_Student` INT(10) NOT NULL AUTO_INCREMENT, `first_name` VARCHAR(50) NULL , `last_name` VARCHAR(50) NOT NULL , `birth_date` DATE NOT NULL , `class_teacher` VARCHAR(50) NOT NULL PRIMARY KEY (`ID_Student`)) ENGINE = InnoDB;

CREATE TABLE `sqlbasics`.`class` (`ID_Class` INT(10) NOT NULL AUTO_INCREMENT, `course` VARCHAR(50) NULL , `class_number` INT(10) NOT NULL , PRIMARY KEY (`ID_Class`)) ENGINE = InnoDB;

CREATE TABLE `sqlbasics`.`student_class_relation` (`ID_Student` INT(10) NOT NULL AUTO_INCREMENT, `ID_Class` VARCHAR(50) NOT NULL ,FOREIGN KEY (`ID_Student`, `ID_Class`)) ENGINE = InnoDB;


-- En este conjunto de 5 tablas tenemos una relacion entre ellas.
-- La tabla de Institute con la de Teachers seria la relacion ONE-TO-ONE.
-- La tabla de teachers con la de Students seria la relacion ONE-TO-MANY.
-- Las tablas de Student, Class y Student_class_relation seria la relacion del MANY-TO-MANY.