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scope.rename with renamed re-export #9266

mischnic opened this Issue Jan 1, 2019 · 3 comments


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mischnic commented Jan 1, 2019

Bug Report

Current Behavior
Running this visitor on the input code

  FunctionDeclaration(path) {
    path.scope.rename(, "a")

renames the reexport as well:

function a() {
  return "YES";
}export { a as x };

export { a as someFunction } from './lib2.js';

Input Code

export function x() {
  return "YES";

export { x as someFunction } from './lib2.js'

Expected behavior/code
The identifier x in the export specifier has nothing to do with the function named x. Renaming the function should not affect the re-export.

function a() {
  return "YES";
}export { a as x };

export { x as someFunction } from './lib2.js';

Babel Configuration (.babelrc, package.json, cli command)

Tested in


  • Babel version(s): 7.2.0
  • Node/npm version: -
  • OS: -
  • Monorepo: -
  • How you are using Babel:

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babel-bot commented Jan 1, 2019

Hey @mischnic! We really appreciate you taking the time to report an issue. The collaborators
on this project attempt to help as many people as possible, but we're a limited number of volunteers,
so it's possible this won't be addressed swiftly.

If you need any help, or just have general Babel or JavaScript questions, we have a vibrant Slack
that typically always has someone willing to help. You can sign-up here
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mischnic commented Jan 2, 2019

A crude fix (if there is no bug deeper in babel): (path.parentPath.parent.source is used to determine re-exports)

diff --git a/packages/babel-traverse/src/scope/lib/renamer.js b/packages/babel-traverse/src/scope/lib/renamer.js
index cdfd9081..6ec401e6 100644
--- a/packages/babel-traverse/src/scope/lib/renamer.js
+++ b/packages/babel-traverse/src/scope/lib/renamer.js
@@ -3,8 +3,13 @@ import splitExportDeclaration from "@babel/helper-split-export-declaration";
 import * as t from "@babel/types";

 const renameVisitor = {
-  ReferencedIdentifier({ node }, state) {
-    if ( === state.oldName) {
+  ReferencedIdentifier(path, state) {
+    const { node } = path;
+    if(t.isExportSpecifier(path.parent) && path.parentPath.parent.source !== null){
+      return;
+    }
     if ( === state.oldName) { = state.newName;

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devongovett commented Jan 12, 2019

Seems like the real issue is that x is in the referencePaths at all. x in the export specifier does not actually reference the local variable x.

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