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variant_qp.py
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variant_qp.py
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from utils.utils import alpha_max, starting_point_qp
import numpy as np
import scipy
def solve_variant_qp(A, b, objectives, tolerance=1e-9, max_it=100):
points = []
# update A by adding column of zeros due to the new variable
m, n = A.shape
k = len(objectives) - 1
# rewrite the everything in a single objective function
enablers = np.zeros(len(objectives))
optimal_points = np.zeros((len(objectives), n))
optimal_solutions = np.zeros((len(objectives),))
enablers[0] = 1
c = update_c(objectives, enablers, optimal_solutions, n)
Q = update_Q(objectives, enablers, optimal_points, n)
x0, lam0, s0 = starting_point_qp(A, b, c, Q)
for iter in range(max_it+1):
print('-' * 80)
print(f'iter [{iter}]:\nx:\n{x0},\nlam:\n{lam0},\ns:\n{s0}')
points.append(x0)
f3, pivots = fact3(A, x0, s0, Q)
rb = A @ x0 - b
rc = A.T @ lam0 + s0 - Q @ x0 - c
rxs = x0 * s0
lam_aff, x_aff, s_aff = solve3(f3, pivots, rb, rc, rxs)
# compute alpha_aff^pr, alpha_aff^dual, mu_aff
alpha_aff_pri = alpha_max(x0, x_aff, 1.0)
alpha_aff_dual = alpha_max(s0, s_aff, 1.0)
mu = np.mean(rxs, dtype=np.float64)
# calculate mu_aff
mu_aff = np.dot(x0 + alpha_aff_pri * x_aff, s0 + alpha_aff_dual * s_aff) / n
# centering parameter sigma
sigma = (mu_aff/mu) ** 3
rb = np.zeros((m,))
rc = np.zeros((n,))
rxs = x_aff * s_aff - sigma * mu
lam_cc, x_cc, s_cc = solve3(f3, pivots, rb, rc, rxs)
# compute the search direction step boundaries
dx = x_aff + x_cc
dlam = lam_aff + lam_cc
ds = s_aff + s_cc
alpha_max_pri = alpha_max(x0, dx, np.inf)
alpha_max_dual = alpha_max(s0, ds, np.inf)
alpha_pri = min(0.99 * alpha_max_pri, 1)
alpha_dual = min(0.99 * alpha_max_dual, 1)
if alpha_pri > 1e308 or alpha_dual > 1e308:
print("this problem is unbounded")
return x0, lam0, s0, False, iter, points
x1 = x0 + alpha_pri * dx
for i in range(k):
x1[n-k+i] = x0[n-k+i] + dx[n-k+i]
lam1 = lam0 + alpha_dual * dlam
s1 = s0 + alpha_dual * ds
# termination
r1 = np.linalg.norm(A @ x1 - b) / (1 + np.linalg.norm(b))
print("rho1", r1)
if r1 < tolerance:
r2 = np.linalg.norm(A.T @ lam1 + s1 - Q @ x1 - c) / (1 + np.linalg.norm(c))
print("rho2", r2)
if r2 < tolerance * 100:
r3 = mu / (1 + np.abs(0.5 * x1.T @ Q @ x1 + np.dot(c, x1)))
print("rho3", r3)
if r3 < tolerance * 1000:
# increment move the enbalers and store the optimal solution
current = np.argmax(enablers)
optimal_points[current] = x1
optimal_solutions[current] = 0.5 * x1.T @ objectives[current]['Q'] @ x1 + objectives[current]['c'].T @ x1
# I have solved the last objectives
if current == enablers.shape[0] - 1:
return x1, lam1, s1, True, iter, points
enablers[current], enablers[current + 1] = 0, 1
print('-' * 80)
print("Next objective")
c = update_c(objectives, enablers, optimal_solutions, n)
Q = update_Q(objectives, enablers, optimal_points, n)
if iter == max_it:
return x1, lam1, s1, False, max_it, points
x0 = x1
lam0 = lam1
s0 = s1
def update_c(objectives, enablers, optimal_solutions, n_var):
# build the c vector
c = np.zeros((n_var,))
c_v = np.zeros((len(objectives) - 1,))
for index, obj in enumerate(objectives):
c += enablers[index] * obj['c']
for i in range(1, len(objectives)):
c_v[i-1] = -optimal_solutions[i-1] * np.sum(enablers[i:])
c[-c_v.shape[0]:] = c_v
print(f"c:\n{c}")
return c
def update_Q(objectives, enablers, optimal_points, n_var):
# build the Q matrix
Q = np.zeros((n_var ,n_var))
Q_v = np.zeros((len(objectives) - 1, n_var))
for index, obj in enumerate(objectives):
Q += enablers[index] * obj['Q']
# add the penalty
for i in range(1, len(objectives)):
Q_v[i-1] = np.sum(enablers[i:]) * (0.5 * optimal_points[i-1].T @ objectives[i-1]['Q'] + objectives[i-1]['c'])
Q[-Q_v.shape[0]:, :] = Q_v
Q[:, -Q_v.shape[0]:] = Q_v.T
print(f"Q:\n{Q}")
return Q
def fact3(A, x, s, Q):
m, n = A.shape
S = np.zeros((s.shape[0], s.shape[0]))
np.fill_diagonal(S, s)
X = np.zeros((x.shape[0], x.shape[0]))
np.fill_diagonal(X, x)
M1 = np.hstack((np.zeros((m, m)), A, np.zeros((m, n))))
M2 = np.hstack((A.T, -Q, np.eye(n,n)))
M3 = np.hstack((np.zeros((n, m)), S, X))
M = np.vstack((M1, M2, M3))
f, pivots = scipy.linalg.lu_factor(M)
return f.astype(np.float64), pivots
def solve3(f, pivots, rb, rc, rxs):
m = rb.shape[0]
n = rc.shape[0]
b = np.hstack((-rb, -rc, -rxs), dtype=np.float64)
# add zeros for the eps variables
b = np.hstack([b, np.zeros((f.shape[0] - b.shape[0],))])
# solve the linear system of equations A * x = b
b = scipy.linalg.lu_solve((f, pivots), b.T)
# extract the solution into separate arrays for dlam, dx, and ds
dlam = b[:m]
dx = b[m:m+n]
ds = b[m+n:]
# return the solutions
return dlam.astype(np.float64), dx.astype(np.float64), ds.astype(np.float64)