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Simplify "!foo || (foo && bar)" as "!foo || bar" #10780
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practicalswift
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Simplify `!foo || (foo && bar)` as `!foo || bar` to Simplify "!foo || (foo && bar)" as "!foo || bar"
Jul 9, 2017
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sipa
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Jul 13, 2017
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practicalswift commentedJul 9, 2017
Simplify
!foo || (foo && bar)as!foo || bar.Rationale: