Expand on contracting carve-out rule test #18723
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jonatack
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Apr 21, 2020
| for _ in range(4): | ||
| # First tx has 3 outputs | ||
| (txid, sent_value) = self.chain_transaction(self.nodes[0], [txid], [vout], value, fee, 3) | ||
| vout = 0 |
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afaict vout is always zero anyway? same for line 63 below...
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removed for line 63, otherwise I think this is more clear personally
| # First tx has 3 outputs | ||
| (txid, sent_value) = self.chain_transaction(self.nodes[0], [txid], [vout], value, fee, 3) | ||
| vout = 0 | ||
| value = sent_value |
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redundant assignment in this loop (and the next one), can remove?
if not, may make sense to extract the loop body to a function
| @@ -79,6 +86,10 @@ def run_test(self): | |||
| # and the second chain should work just fine | |||
| self.chain_transaction(self.nodes[0], [second_chain], [0], second_chain_value, fee, 1) | |||
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| # But now that we're at the additional carve-out limit, the third base output being spent will be rejected | |||
| # For both ancestor's descendant limits | |||
| assert_raises_rpc_error(-26, "too-long-mempool-chain, too many descendants", self.chain_transaction, self.nodes[0], [chain[0][0]], [2], chain[0][1], fee, 1) | |||
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"too-long-mempool-chain, too many descendants" used 5x, could hoist to a TOO_MANY_DESCENDANTS constant
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Testing the "one more" on top of "one more", making sure this is rejected.