diff --git a/README.md b/README.md
index 831cec2..cc3ea27 100644
--- a/README.md
+++ b/README.md
@@ -11,19 +11,19 @@ ____
 Ok, we’re ready to being. Type lein repl or cake repl, this will drop you into the Clojure prompt. First lets double check that everything went ok. Enter the following at the Clojure REPL:
 
 ```clj
-user=>(require 'clojure.core.logic.minikanren)
+user=> (require 'clojure.core.logic.minikanren)
 ```
 
 The REPL should print nil and it should return control to you. If it doesn’t file an issue for this tutorial and I’ll look into it. If all goes well run the following:
 
 ```clj
-user=>(load "logic_tutorial/tut1")
+user=> (load "logic_tutorial/tut1")
 ```
 
 You’ll see some harmless warning, then run the following:
 
 ```clj
-user=>(in-ns 'logic-tutorial.tut1)
+user=> (in-ns 'logic-tutorial.tut1)
 ```
 
 Your prompt will change and you’re now working in a place that has the magic of logic programming available to you. It will show logic-tutorial.tut1, we're going show tut1 to keep things a bit more readable.
@@ -34,93 +34,93 @@ Baby Steps
 Unlike most programming systems, with relational programming we can actually ask the computer questions. But before we ask the computer questions, we need define some facts! The first thing we want the computer to know about is that there are men:
 
 ```clj
-tut1=>(defrel man x)
+tut1=> (defrel man x)
 #'tut1/man
 ```
 
 And then we want to define some men:
 
 ```clj
-tut1=>(fact man 'Bob)
+tut1=> (fact man 'Bob)
 nil
-tut1=>(fact man 'John)
+tut1=> (fact man 'John)
 nil
 ```
 
 No we can ask who are men. First we have to formulate a question and then tell the computer we want the computer to find answers to our question:
 
 ```clj
-tut1=> (run 1 [q] (man q))
+tut1=>  (run 1 [q] (man q))
 (John)
 ```
 
 We’re asking the computer to give us at least one answer to the question - “Who is a man?”.  We can ask for more than one answer:
 
 ```clj
-tut1=>(run 2 [q] (man q))
+tut1=> (run 2 [q] (man q))
 (John Bob)
 ```
 
 Now that is pretty cool. What happens if we ask for more answers?
 
 ```clj
-tut1=>(run 3 [q] (man q))
+tut1=> (run 3 [q] (man q))
 (John Bob)
 ```
 
 The same result. That’s because we’ve only told the computer that two men exist in the world. It can’t give results for things it doesn’t know about. Let’s define another kind of relationship and a fact:
 
 ```clj
-tut1=>(defrel fun x)
+tut1=> (defrel fun x)
 #'tut1/fun
-tut1=>(fact fun 'Bob)
+tut1=> (fact fun 'Bob)
 nil
 ```
 
 Let’s ask a new kind of question:
 
 ```clj
-tut1=>(run* [q] (man q) (fun q))
+tut1=> (run* [q] (man q) (fun q))
 (Bob)
 ```
 
 There’s a couple of new things going on here. We’re asking who is both a man and who is fun. Now this getting interesting. Enter in the following:
 
 ```clj
-tut1=>(defrel woman x)
+tut1=> (defrel woman x)
 #'tut1/woman
-tut1=>(fact woman 'Lucy)
+tut1=> (fact woman 'Lucy)
 nil
-tut1=>(fact woman 'Mary)
+tut1=> (fact woman 'Mary)
 nil
-tut1=>(defrel likes x y)
+tut1=> (defrel likes x y)
 #'tut1/likes
 ```
 
 Relations don’t have to be a about a single entity. We can define relationship between things!
 
 ```clj
-tut1=>(fact likes 'Bob 'Mary)
+tut1=> (fact likes 'Bob 'Mary)
 nil
-tut1=>(fact likes 'John 'Lucy)
+tut1=> (fact likes 'John 'Lucy)
 nil
-tut1=>(run* [q] (likes 'Bob q))
+tut1=> (run* [q] (likes 'Bob q))
 (Mary)
 ```
 
 We can now ask who likes who! Let's try this:
 
 ```clj
-tut1=>(run* [q] (likes 'Mary q))
+tut1=> (run* [q] (likes 'Mary q))
 ()
 ```
 
 Hmm that doesn’t work. This is because we never actually said who Mary liked, only that Bob liked Mary:
 
 ```clj
-tut1=>(fact likes 'Mary 'Bob)
+tut1=> (fact likes 'Mary 'Bob)
 nil
-tut1=>(run* [q] (exist [x y] (== q [x y]) (likes x y) ))
+tut1=> (run* [q] (exist [x y] (== q [x y]) (likes x y) ))
 ([Bob Mary] [John Lucy])
 ```
 
@@ -129,7 +129,7 @@ Wow that’s a lot of new information. The exist expression isn’t something we
 I’ve done a lot of lying in the last paragraph. Run the following:
 
 ```clj
-tut1=>(run* [q] (exist [x y] (likes x y) (== q [x y])))
+tut1=> (run* [q] (exist [x y] (likes x y) (== q [x y])))
 ([Bob Mary] [John Lucy])
 ```
 
@@ -141,25 +141,25 @@ Genealogy
 We’ve actually defined some interesting relations in this namespace that we’ll use before we take a closer look at them:
 
 ```clj
-tut1=>(fact parent 'John 'Bobby)
+tut1=> (fact parent 'John 'Bobby)
 nil
-tut1=>(fact male 'Bobby)
+tut1=> (fact male 'Bobby)
 nil
 ```
 
 We can now run this query:
 
 ```clj
-tut1=>(run* [q] (son q 'John))
+tut1=> (run* [q] (son q 'John))
 (Bobby)
 ```
 
 Let’s add another fact:
 
 ```clj
-tut1=>(fact parent 'George 'John) 
+tut1=> (fact parent 'George 'John) 
 nil
-tut1=>(run* [q] (grandparent q 'Bobby))
+tut1=> (run* [q] (grandparent q 'Bobby))
 (George)
 ```