Algorithms for tiling the plane with Wang tiles [Public domain]
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README.md

Wang Tilers

This repository contains descriptions and implementations of algorithms that generate Wang titlings.

(In fact, it currently contains only one implementation of only one such algorithm, but it may, in the future, contain more.)

You can read the linked article for more information, but in brief, a Wang tiling is a tiling of the plane by a set of tiles which, by their nature, tile the plane aperiodically — the tiling pattern never quite repeats itself.

Even more interestingly, each such aperiodic tiling corresponds to a Turing machine that does not halt.

Backtracking Wang Tiler

This is a naïve algorithm which works as follows:

  • Place a tile at the origin.
  • Place successive tiles in a spiral: from the origin, move right, then down, then left, then up, then right again etc., keeping always adjacent to tiles that have previously been placed.
  • Before placing a tile, compute all the allowable possibilities for tiles at that position.
  • If there are no allowable possibilities, backtrack: change the previously-placed tile to the next allowable possibility for it ("retry" it) and continue; and if there are no more allowable possibilities for that previous tile, delete it and retry the tile previous to it, and so forth.

Given that Wang tiles do tile the plane (albeit aperiodically,) this will eventually generate a tiling.

However, it is incredibly efficient, for the following reason: it is entirely possible that it will lay down a "wall" against which it is impossible to place any series of Wang tiles, because it contains an "impossible spot." While trying to place tiles against this wall, it will keep hitting the "impossible spot" and backtracking, trying possibility after possibility until it backtracks all the way around the spiral and finally replaces the "impossible spot" with something not-impossible-to-tile-against.

It is, however, interesting to watch.

This algorithm has been implemented in Javascript, using the yoob.js framework, depicting the tiles on an HTML5 canvas.

The implementation uses the 13 tiles given by Culik in 1996 (see article linked to above), but it would be quite easy to modify it to use any given set of tiles (even ones which tile periodically, for whatever it's worth.)

Other possible algorithms

Lookahead

It should be possible to refine the backtracking algorithm by adding some lookahead, and ensuring early that no "impossible spots" are created.

In a sense, if you could look ahead infinitely far, you wouldn't need to backtrack at all. Of course, that wouldn't be a practical algorithm; in fact, that strongly implies that you will always need backtracking (or something equivalent to it.)

Bogo-tile

It might be possible to use "reconciliation" instead of backtracking, in an algorithm something like:

  • Place the initial tile randomly.
  • Choose a random position adjacent to a placed tile.
  • Place a tile there.
  • If there are any tiles adjacent to it that don't match, delete them.
    • And if it is not possible to place a tile in that now-empty position, delete the tile you just placed.
  • Repeat from step 2.

Once a cluster of tiles do fit together, they will only be deleted starting from the edges. But assuming fits are more likely than clashes (are they??), such clusters would tend to grow, rather than shrink, and eventually tile the plane. (Shrinking is the equivalent to backtracking in this scheme.)

I expect this would be even less efficient than explicit backtracking. But it, too, might be interesting to watch. And it has the nice properties of being simpler and more "statistical".

Turing machine translation

This one should be obvious, since it's how Berger showed the domino problem is undecidable: since every Turing machine which does not halt corresponds to a possible Wang tiling, just pick a Turing machine which you know does not halt, and translate it into a tiling.

Thing is, I haven't looked at Berger's paper, and don't know if his translation from TM's to tilings (and back) is constructive. If it isn't, well, there's no easy algorithm to be had.

There is also the small complication that you'd have to prove that the Turing machine never halts, first. This isn't insurmountable; the Halting Problem is only undecidable in general, and given a particular TM, we can sometimes prove that it does not halt. But it does kind of place a practical limit on the number of tilings you could generate using this method.