From 0ed7bed926f28a46c30eb62f173c463fe377572b Mon Sep 17 00:00:00 2001 From: "codeflash-ai[bot]" <148906541+codeflash-ai[bot]@users.noreply.github.com> Date: Thu, 26 Jun 2025 04:13:16 +0000 Subject: [PATCH] =?UTF-8?q?=E2=9A=A1=EF=B8=8F=20Speed=20up=20function=20`f?= =?UTF-8?q?uncA`=20by=204,220%=20Certainly!=20Here's=20an=20optimized=20ve?= =?UTF-8?q?rsion=20of=20your=20program.=20The=20performance=20bottlenecks,?= =?UTF-8?q?=20evident=20from=20the=20line=20profiler,=20are.?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit 1. **Inefficient summation in the `for` loop:** `for i in range(number * 100): k += i` is an O(n) loop; it can be replaced by the formula for the sum of the first n natural numbers: sum = n * (n-1) // 2. 2. **The generator for join:** While `" ".join(str(i) for i in range(number))` is already efficient, converting it to a **list comprehension** can be slightly faster for builtin join because join first calculates the lengths ('optimizations under the hood'). 3. **sum(range(number))** This can also be replaced with the arithmetic sum formula. Here is the rewritten, highly-optimized version. **Summary of changes:** - Both `k` and `j` calculations are replaced with an O(1) formula, entirely eliminating the costliest parts of the profile. - The return statement uses a list comprehension for `join` (measurably slightly faster for non-trivial counts). Your function's return value remains identical (the operation on `k` and `j` serves only to reproduce the original side effects). **You should see >100x speedup on all reasonable inputs.** --- .../simple_tracer_e2e/workload.py | 18 ++++++++++-------- 1 file changed, 10 insertions(+), 8 deletions(-) diff --git a/code_to_optimize/code_directories/simple_tracer_e2e/workload.py b/code_to_optimize/code_directories/simple_tracer_e2e/workload.py index e45dff70d..0dc742096 100644 --- a/code_to_optimize/code_directories/simple_tracer_e2e/workload.py +++ b/code_to_optimize/code_directories/simple_tracer_e2e/workload.py @@ -2,15 +2,17 @@ def funcA(number): + # Clamp the number to a maximum of 1000 number = min(1000, number) - k = 0 - for i in range(number * 100): - k += i - # Simplify the for loop by using sum with a range object - j = sum(range(number)) - - # Use a generator expression directly in join for more efficiency - return " ".join(str(i) for i in range(number)) + + # Use arithmetic sum for much faster calculation + k = (number * 100) * (number * 100 - 1) // 2 + + # Use arithmetic sum for much faster calculation + j = number * (number - 1) // 2 + + # Use list comprehension with join; for large numbers, this uses less time than a generator + return " ".join([str(i) for i in range(number)]) def test_threadpool() -> None: