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Updated readme, and added MIT license

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commit 9b699c51e3b9fd31723b1187043485703bd676cf 1 parent 82bb511
@coderholic authored
Showing with 25 additions and 2 deletions.
  1. +21 −0 LICENSE
  2. +4 −2 README
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21 LICENSE
@@ -0,0 +1,21 @@
+The MIT License
+
+Copyright (c) 2010 Ben Dowling
+
+Permission is hereby granted, free of charge, to any person obtaining a copy
+of this software and associated documentation files (the "Software"), to deal
+in the Software without restriction, including without limitation the rights
+to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
+copies of the Software, and to permit persons to whom the Software is
+furnished to do so, subject to the following conditions:
+
+The above copyright notice and this permission notice shall be included in
+all copies or substantial portions of the Software.
+
+THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
+IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
+FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
+AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
+LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
+OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
+THE SOFTWARE.
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6 README
@@ -8,12 +8,14 @@ the way in which it gets cleaned up.
Includes 234 counties, 2,610 regions, 97,949 cities and 606 districts
+For more information and examples see http://www.coderholic.com/django-cities-countries-regions-cities-and-districts-for-django/
+
Examples:
=========
Finding all London boroughs:
>>> london = City.objects.filter(country__name='United Kingdom').get(name='London')
->>> boroughs = Districts.objects.filter(city=london)
+>>> boroughs = District.objects.filter(city=london)
Nearest city to a given lat,lon:
@@ -23,4 +25,4 @@ Nearest city to a given lat,lon:
5 Nearest cities to London:
>>> london = City.objects.filter(country__name='United Kingdom').get(name='London')
->>> nearest = City.objects.distance(london.location).exclude(id=london.id).orderby('distance')[:5]
+>>> nearest = City.objects.distance(london.location).exclude(id=london.id).order_by('distance')[:5]
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